前往:如何合并两个(或多个)http.ServeMux? [英] Go: How to combine two (or more) http.ServeMux?

问题描述

假设您有两个 http.ServeMux 实例，并且您希望它们在相同的端口号上提供服务，就像这样:

Given that you have two instances of http.ServeMux, and you wish for them to be served at the same port number, like so:

    muxA, muxB http.ServeMux
    //initialise muxA
    //initialise muxB
    combinedMux := combineMux([muxA, muxB])
    http.ListenAndServe(":8080", combinedMux)

如何编写如上所述的 combinedMux 函数?

How would one go about writing the combinedMux function, as described above?

...还是有另一种方法可以完成同一件事?

... or is there an alternative way to accomplish the same thing?

推荐答案

由于 http.ServeMux 也是 http.Handler ，因此您可以轻松地将一个多路复用器嵌套在另一个中，即使在相同的端口和相同的主机名上也是如此.这是执行此操作的一个示例:

Because an http.ServeMux is also an http.Handler you can easily nest one mux inside another, even on the same port and same hostname. Here's one example of doing that:

rootMux := http.NewServeMux()
subMux := http.NewServeMux()

// This will end up handling /top_path/sub_path
subMux.HandleFunc("/sub_path", myHandleFunc)

// Use the StripPrefix here to make sure the URL has been mapped
// to a path the subMux can read
rootMux.Handle("/top_path/", http.StripPrefix("/top_path", subMux))

http.ListenAndServe(":8000", rootMux)

请注意，如果没有该 http.StripPrefix()调用，则需要处理整个路径位于下多路复用器中.

Note that without that http.StripPrefix() call, you would need to handle the whole path in the lower mux.

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