在Go中解组XML [英] Unmarshaling XML in Go

问题描述

我有以下xml文件":

I have the following xml "file":

<pinnacle_line_feed>
    <PinnacleFeedTime>1439954818555</PinnacleFeedTime>
    <lastContest>34317132</lastContest>
    <lastGame>218491030</lastGame>
    <events>
        <event>
            <event_datetimeGMT>2015-08-21 09:50</event_datetimeGMT>
            <gamenumber>483406220</gamenumber>
            <sporttype>Aussie Rules</sporttype>
            <league>AFL</league>
            <IsLive>No</IsLive>
            <participants>
                <participant>
                    <participant_name>Hawthorn Hawks</participant_name>
                    <contestantnum>1251</contestantnum>
                    <rotnum>1251</rotnum>
                    <visiting_home_draw>Visiting</visiting_home_draw>
                    </participant>
                <participant>
                    <participant_name>Port Adelaide Power</participant_name>
                    <contestantnum>1252</contestantnum>
                    <rotnum>1252</rotnum>
                    <visiting_home_draw>Home</visiting_home_draw>
                </participant>
            </participants>
            <periods></periods>
        </event>
    </events>
</pinnacle_line_feed>

我正在尝试用Golang解析它，到目前为止已经写了以下内容:

I am attempting to parse this with Golang, and have written the below thus far:

package main
import (
	"fmt"
	"encoding/xml"
)

type Participant struct {
	XMLName            xml.Name `xml:"participant"`
	participant_name   string `xml:"participant_name"`
	contestantnum      int `xml:"contestantnum"`
	rotnum             int `xml:"rotnum"`
	visiting_home_draw string `xml:"visiting_home_draw"`
}

type Event struct {
	XMLName           xml.Name `xml:"event"`
	event_datetimeGMT string `xml:"event_datetimeGMT"`
	gamenumber        string `xml:"gamenumber"`
	sporttype         string `xml:"sporttype"`
	league            string `xml:"league"`
	IsLive            string `xml:"IsLive"`
	Participant       []Participant `xml:"participant"`
}

type Events struct {
	XMLName xml.Name `xml:"events"`
	Event   []Event `xml:"event"`
}

type Pinnacle_Line_Feed struct {
	XMLName          xml.Name `xml:"pinnacle_line_feed"`
	PinnacleFeedTime string `xml:"PinnacleFeedTime"`
	lastContest      string `xml:"lastContest"`
	lastGame         string `xml:"lastGame"`
	Events           []Events `xml:"events"`
}

坦率地说，我对Golang中的深层嵌套xml解析进行了相当多的研究，但在此代码的Unmarshal部分中却找不到很多帮助.理想情况下，代码将返回类似于python字典的内容，例如

Frankly, I have researched quite a bit on deep nested xml parsing in Golang, and I haven't found much to help with the Unmarshal portion of this code. Ideally, the code would return something similar to a python dictionary, such as,

{event_datetimeGMT:2015-08-21，游戏号:483406220，...，visiting_home_draw:主场"}

{event_datetimeGMT: 2015-08-21, gamenumber: 483406220, ... , visiting_home_draw: "Home"}

基于以下Nicolas的评论，我添加了以下内容.这样可以正常运行，但是会产生空结果.

Based on Nicolas's comment below, I added the following. This runs without error, but produces an empty result.

 func main() {
         pinny_xml := `
         <pinnacle_line_feed>
            <PinnacleFeedTime>1439954818555</PinnacleFeedTime>
            <lastContest>34317132</lastContest>
            <lastGame>218491030</lastGame>
            <events>
                <event>
                    <event_datetimeGMT>2015-08-21 09:50</event_datetimeGMT>
                    <gamenumber>483406220</gamenumber>
                    <sporttype>Aussie Rules</sporttype>
                    <league>AFL</league>
                    <IsLive>No</IsLive>
                    <participants>
                        <participant>
                            <participant_name>Hawthorn Hawks</participant_name>
                            <contestantnum>1251</contestantnum>
                            <rotnum>1251</rotnum>
                            <visiting_home_draw>Visiting</visiting_home_draw>
                            </participant>
                        <participant>
                            <participant_name>Port Adelaide Power</participant_name>
                            <contestantnum>1252</contestantnum>
                            <rotnum>1252</rotnum>
                            <visiting_home_draw>Home</visiting_home_draw>
                        </participant>
                    </participants>
                    <periods></periods>
                </event>
            </events>
        </pinnacle_line_feed>
        `

        xmlReader := bytes.NewReader([]byte(pinny_xml))
        yourPinnacleLineFeed := new(Pinnacle_Line_Feed)
        if err := xml.NewDecoder(xmlReader).Decode(yourPinnacleLineFeed); err != nil {
            return // or log.Panic(err.Error()) if in main
        }
}

推荐答案

您可以这样做:

xmlReader := bytes.NewReader([]byte(your_xml_as_a_string_here))
yourPinnacleLineFeed := new(Pinnacle_Line_Feed)
if err := xml.NewDecoder(xmlReader).Decode(yourPinnacleLineFeed); err != nil {
    return // or log.Panic(err.Error()) if in main
}

这是如果您的xml文件"是一个字符串.如果要从互联网上获取它(例如，作为http响应的正文)，则resp.Body已经可以满足Reader的要求，因此您可以跳过第一行.如果要在OS上打开真实文件，则也可以使用Reader作为打开它的方式.

This is if your xml "file" is a string. If you're getting it from the internet (as the body of an http response for instance), resp.Body is already going to satisfy a Reader, so you can skip the first line. If you're opening a real file on the OS, you can also open it as a Reader, same thing.

还有两件事:

• 为了简单明了，您可以嵌套结构并删除xml.Name字段
• 我还注意到您忘记了结构中的参与者级别，导致没有参与者被编组

这是一个更简单的版本，可以正常工作，它具有一个可选功能来检查结果中包含的内容:

Here's a more simple version that works, with an optional function to check what you have inside the results :

package main

import (
    "bytes"
    "encoding/json"
    "encoding/xml"
    "fmt"
    "log"
)

type Pinnacle_Line_Feed struct {
    PinnacleFeedTime string `xml:"PinnacleFeedTime"`
    LastContest      string `xml:"lastContest"`
    LastGame         string `xml:"lastGame"`
    Events           struct {
        Event []struct {
            Event_datetimeGMT string `xml:"event_datetimeGMT"`
            Gamenumber        string `xml:"gamenumber"`
            Sporttype         string `xml:"sporttype"`
            League            string `xml:"league"`
            IsLive            string `xml:"IsLive"`
            Participants      struct {
                Participant []struct {
                    Participant_name   string `xml:"participant_name"`
                    Contestantnum      int    `xml:"contestantnum"`
                    Rotnum             int    `xml:"rotnum"`
                    Visiting_home_draw string `xml:"visiting_home_draw"`
                } `xml:"participant"`
            } `xml:"participants"`
        } `xml:"event"`
    } `xml:"events"`
}

func main() {
    pinny_xml := `
         <pinnacle_line_feed>
            <PinnacleFeedTime>1439954818555</PinnacleFeedTime>
            <lastContest>34317132</lastContest>
            <lastGame>218491030</lastGame>
            <events>
                <event>
                    <event_datetimeGMT>2015-08-21 09:50</event_datetimeGMT>
                    <gamenumber>483406220</gamenumber>
                    <sporttype>Aussie Rules</sporttype>
                    <league>AFL</league>
                    <IsLive>No</IsLive>
                    <participants>
                        <participant>
                            <participant_name>Hawthorn Hawks</participant_name>
                            <contestantnum>1251</contestantnum>
                            <rotnum>1251</rotnum>
                            <visiting_home_draw>Visiting</visiting_home_draw>
                        </participant>
                        <participant>
                            <participant_name>Port Adelaide Power</participant_name>
                            <contestantnum>1252</contestantnum>
                            <rotnum>1252</rotnum>
                            <visiting_home_draw>Home</visiting_home_draw>
                        </participant>
                    </participants>
                    <periods></periods>
                </event>
            </events>
        </pinnacle_line_feed>
    `

    xmlReader := bytes.NewReader([]byte(pinny_xml))
    yourPinnacleLineFeed := new(Pinnacle_Line_Feed)
    if err := xml.NewDecoder(xmlReader).Decode(yourPinnacleLineFeed); err != nil {
        log.Panic(err.Error())
    }

    printX(yourPinnacleLineFeed)
}

func printX(x interface{}) (err error) {
    var xBytes []byte
    xBytes, err = json.MarshalIndent(x, "", "  ")
    if err != nil {
        return
    }
    fmt.Println(string(xBytes))
    return
}

这篇关于在Go中解组XML的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！