将图像从* image.YCbCr转换为* image.RGBA [英] Convert image from *image.YCbCr to *image.RGBA
问题描述
我正在从磁盘加载jpeg，我想在其中执行一些RGBA操作.
I am loading a jpeg from the disk, and I would like to do some RGBA operations on it.
但是，由于jpeg不是RGBA，因此当我尝试使用jpeg时出现错误:
However, since the jpeg is not RGBA, i get an error when I try to use it as such:
thumbnail,err:=jpeg.Decode(imageAsReader)
...
return thumbnail.(*image.RGBA)
产生错误:
interface conversion: image.Image is *image.YCbCr, not *image.RGBA
将图像加载到内存后，是否有一种简单的方法可以将图像转换为RGBA?(其他操作稍后将在RGBA中进行，所以这是我要在内存中使用的颜色模型.)
Is there an easy way to convert the image to RGBA once I have loaded it in memory? (Other operations are in RGBA later on, so that is the color model I want to use in memory).
推荐答案
正如评论所建议的，您必须创建一个新图像并将其绘制到其中:b:= thumbnail.Bounds()m:= image.NewRGBA(image.Rect(0，0，b.Dx()，b.Dy()))draw.Draw(m，m.Bounds()，缩略图，b.Min，draw.Src)
As the comments suggest, you have to create a new image and draw into it:
b := thumbnail.Bounds()
m := image.NewRGBA(image.Rect(0, 0, b.Dx(), b.Dy()))
draw.Draw(m, m.Bounds(), thumbnail, b.Min, draw.Src)
YCbCr是二次采样的图像，因此它不直接映射到RGBA的每像素4字节.
YCbCr is a sub-sampled image, so it doesn't map directly to the 4-bytes-per-pixel of RGBA.
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