随机子串错误?< TypeError:在对象中找不到函数子字符串.... [英] Random substring error? "TypeError: Cannot find function substring in object..."

问题描述

错误是:

TypeError:在对象中找不到函数子字符串

代码循环遍历10个值，并检查第一个字符是否为数字.

The code loops through 10 values, checking for the first character being a number.

function TypeErrorMystery() {

  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var s = ss.getActiveSheet();

  //loop from cell 1-10
  for (var i = 0; i < 10; i++) {
    var range = s.getRange(i + 1, 1)
    var substring1 = range.getValue().substring(0, 1);
      //if first character in cell is #
      if (substring1 === "#" ) {
         //write over it with "success"
         range.setValue("success");
      }
   };
}

确切的错误是:

TypeError:在对象3中找不到函数子字符串(第9行，文件代码")，

第9行是:

var substring1 = range.getValue().substring(0, 1);

推荐答案

单元格中的值为数字3. substring()方法在应用于数字时会引发错误.您应该检查返回的值的类型.

The value in the cell is the number 3. The substring() method throws an error when being applied to a number. You should check the type of value that is returned.

if (typeof thisCellValue === 'number') {continue;};//Skip over numbers

完整代码:

function TypeErrorMystery() {

  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var s = ss.getActiveSheet();
  var range,
      substring1,
      thisCellValue;

  //loop from cell 1-10
  for (var i = 0; i < 10; i++) {
    range = s.getRange(i + 1, 1)
    thisCellValue = range.getValue();
    Logger.log('typeof thisCellValue: ' + typeof thisCellValue);

    if (typeof thisCellValue === 'number') {continue;};

    substring1 = thisCellValue.substring(0, 1);

    //if first character in cell is #
    if (substring1 === "#" ) {
      //write over it with "success"
      range.setValue("success");
    }
  };
};

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