Google Script中的document.getelementbyId无法正常工作 [英] document.getelementbyId in Google Script not working
问题描述
我正在尝试制作一个Google脚本Web应用程序，该应用程序从HTML表单获取输入并将输入传递给脚本.现在，该函数失败了，因为 document.getelementbyId('text')返回的是 null 而不是实际的表单值.我该如何解决?
I am trying to make a google script web app that takes input from an HTML form and passes the input to a script. Right now, the function is failing because document.getelementbyId('text') returns null instead of the actual form value. How can I fix this?
Index.html
<!DOCTYPE html>
<html>
<head>
<base target="_top">
<script>
// Prevent forms from submitting.
function preventFormSubmit() {
var forms = document.querySelectorAll('form');
for (var i = 0; i < forms.length; i++) {
forms[i].addEventListener('submit', function(event) {
event.preventDefault();
});
}
}
window.addEventListener('load', preventFormSubmit);
function handleFormSubmit() {
var formObject = document.getElementById('text');
google.script.run.withSuccessHandler(setTable).getSportData(formObject);
console.log(formObject);
}
function setTable(data) {
var div = document.getElementById('output');
div.innerHTML = createTable(data);
}
/**
* Adds an html table
*/
function createTable(tableData) {
var table = document.createElement('table');
var tableBody = document.createElement('tbody');
tableData.forEach(function(rowData) {
var row = document.createElement('tr');
rowData.forEach(function(cellData) {
var cell = document.createElement('td');
cell.appendChild(document.createTextNode(cellData));
row.appendChild(cell);
});
tableBody.appendChild(row);
});
table.appendChild(tableBody);
document.body.appendChild(table);
}
</script>
</head>
<body>
<form id="myForm" onsubmit="handleFormSubmit()">
<input name="text" type="text" />
<input type="submit" value="Submit" />
</form>
<div id="output"></div>
</body>
</html>
Code.gs
//Initalization of global variables for use by the script's custom functions
var ss = SpreadsheetApp.openById("spreadsheetID");
var sheet = ss.getSheetByName("Sheet1");
var sportsFromSheet = sheet.getRange("D4:D12");
var namesFromSheet = sheet.getRange("B4:B12").getValues();
var timesFromSheet = sheet.getRange("A4:A12").getValues();
var NAMES = [];
var TIMES = [];
/**
* Handles HTTP GET requests to the published web app.
* @return {HtmlOutput} The HTML page to be served.
*/
function doGet() {
return HtmlService.createHtmlOutputFromFile('Index');
}
/**
* Gets both names and Times of checked-in people from the spreadsheet from the private function getOutput.
* @return {HtmlOutput} A 2D array containing the names and times.
*/
function getSportData(formObject) {
getNamesInSport(formObject);
getTimesInSport(formObject);
var OUTPUT = [
[NAMES],
[TIMES]
];
return OUTPUT;
}
//Puts the names of every person from an inputted sport into an array.
function getNamesInSport(input) {
var data = sportsFromSheet.getValues();
for (var i = 0; i < data.length; i++) {
if(data[i] == input){
NAMES.push(namesFromSheet[i][0]);
}
}
}
//Puts the times of every person from an inputted sport into an array.
function getTimesInSport(input){
var data = sportsFromSheet.getValues();
for (var i = 0; i < data.length; i ++) {
if(data[i] == input){
TIMES.push(timesFromSheet[i][0]);
}
}
}
推荐答案
Duplicate of Why does jQuery or a DOM method such as getElementById not find the element?.
您似乎已经回答了自己的问题.
You appear to have answered your own question.
document.getElementById('text')返回 null ，因为...您没有带 id ="text" 的元素.
document.getElementById 将返回 null
如果具有指定ID的元素不在文档中.( Mozilla开发人员网络)
解决方案是< input type ="text"名称=文本" id ="text" >
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