在下拉菜单输入中设置Google地方信息的“类型" [英] Setting Google Places 'Types' on Dropdown Input

问题描述

我正在使用Google Places API列出运输服务的接送地点.我们有两个字段，在输入时会自动建议结果.

I'm using the Google Places API to list pick up and drop off locations for a transportation service. We have two fields that, when typed in, autosuggest results.

将下拉菜单#transport-type设置为第一个选项，值= 1时，则输入字段#pick-up-location应在其结果中添加类型"机场.

When a a dropdown, #transport-type, is set to the first option, value = 1, then the input field, #pick-up-location, should have 'types' airport added to its results.

JS:

function transport_types() {
 if ($('#transport-type').val() == 1) { 
     var input = document.getElementById('pick-up-location');
     var options = { types: ['airport'] };
     autocomplete = new google.maps.places.Autocomplete(input, options);
 }
 if ($('#transport-type').val() == 2) {
     var input = document.getElementById('drop-off-location');
     var options = { types: ['airport'] };
     autocomplete = new google.maps.places.Autocomplete(input, options);
 }
 google.maps.event.addDomListener(window, 'load', initialize);
}

下拉HTML:

<select id="transport-type" name="TransNeeded" required="true" tabindex="101" onChange="transport_types();">
  <option value='0' selected='selected'>Where do you want to go?</option>
  <option value='1' onfocus="enableGoogle('', true);"  id="pick-up-type">Pick-Up Location is an Airport</option>
  <option value='2' onfocus="enableGoogle('', true);" id="drop-off-type">Drop-Off Location is an Airport</option>
  <option value='3' onfocus="enableGoogle('', true);" id="point-point-type">Point to Point or Charter</option>
</select>    

输入HTML:

<input type="text" id="pick-up-location" name="PUFullAddress" tabindex="104" value="Pick-Up Location" required="true" 
  onblur="if(this.value.length==0) { $('#pick-up-location').attr('value', ''); }"
  onkeypress="delay(50);" 
  onfocus="enableGoogle('PU', false);" 
/>

<input id="drop-off-location" name="DOFullAddress" type="text" tabindex="105" value="Drop-Off Location" required="true" 
 onblur="if(this.value.length==0) { $('#drop-off-location').attr('value', ' '); }"
 onkeypress="delay(50);" 
 onfocus="enableGoogle('DO', false);" 
/>

我不是经验最丰富的jQuery程序员，因此它甚至可能是语法问题.感谢您提供的任何见解.

I'm not the most seasoned jQuery programmer, so it could even be an issue of syntax. I appreciate any insight you guys can provide.

感谢您的时间！

推荐答案

您缺少右括号，还有一个多余的内容；尝试以下

You're missing a close bracket and have an extra ; Try the following

 if ($('#transport-type').attr('value', '1')) {

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