在groovy中获取标记化字符串中的最后一个单词 [英] getting last word in a tokenized string in groovy

问题描述

一个基本的字符串处理问题..我有一个像val1.val2.val3 ..... valN这样的标记化字符串如何从上面的字符串中获取最后一个单词valN.

A basic String handling question..I have a tokenized String like val1.val2.val3.....valN How do I get the last word valN from the string above.

推荐答案

如果将负索引n传递给

If you pass a negative index n to the subscript operator in a List, you get n-th last element. Therefore, the -1 element is the last one:

def words = 'val1.val2.val3'
def last = words.tokenize('.')[-1]
assert last == 'val3'

更新:您还可以找到更具可读性的

Update: You also have the, arguably more readable, last method:

def last = words.tokenize('.').last()

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