Jenkins使用Groovy读取Jenkinsfile中文件的特定行 [英] Jenkins Read a Specific Line of a File in Jenkinsfile with Groovy

问题描述

我正在尝试使用 Groovy 在Jenkins stage 中读取 html 文件的特定行，并将其内容保存到环境变量中.问题是不允许使用 File 和 readLines().

I am trying to read a specific line of an html file in a Jenkins stage with Groovy and save its contents to an environment variable. The problem is, File and readLines() are not allowed.

我能够使用以下文件加载文件

I am able to load a file with

env.WORKSPACE = pwd()
def file = readFile "${env.WORKSPACE}/file.html"

在此答案中提供

但是如何立即访问 n 行的内容?我正在使用 Jenkins 2.32

But how can I access instantly to the contents of line n? I am using Jenkins 2.32

推荐答案

我从注释中尝试了有关tim_yates的建议，但也禁止了 System .最终对我有用的只是将 System.getProperty("line.separator")更改为新的行字符"\ n" .

I Tried the suggestion of tim_yates from the comments but System was also forbidden. What ultimately worked for me was just changing System.getProperty("line.separator") to new line character "\n".

因此，完整的答案很简单:

So the full answer was in its simplicity:

file.split("\n")[n]

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