如何在Haskell中打印相同的字符n次 [英] How to print the same char n times in Haskell

问题描述

我想打印一个在字符串下划线n次的字符，在Haskell中字符串的长度为n.

I would like to print a char underlining a String n times, with n the length of the String in Haskell.

我应该怎么做?

我的字符串是:可用字符(x)"并且我想在该句子下划线加一个char，该句子的长度应与"Available Chars(x)"完全相同.但是x是一个整数，因此它可以是"1"或"10"或"1000"等.因此长度是可变的.我有长度，但是只要字符串是...，我都不知道如何打印该字符...

My String is: "Available Chars (x)" and I want to have a char underlining that sentence, which should have exactly the same length as the "Available Chars (x)". But x is an int, so it could be "1" or "10" or "1000" etc.. so the length is variable. I got the length but i didnt know how to print that char as long as the string is...

推荐答案

使用这将为您提供一个字符串，该字符串是字符-"的n倍，其中n是输入字符串的长度.等同于:

This will give you a string which is n times the character '-' where n is the length of the input string. It is the same as:

underline = map (const '-')

然后，您可以像这样使用它(例如，如果 yourString ="Available Chars(111)" ):

You can then use it like this (if for example yourString = "Available Chars (111)"):

> putStrLn yourString >> putStrLn (underline yourString)
Available Chars (111)
---------------------

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