如何跳过xml-conduit中的元素 [英] How to skip elements in xml-conduit

问题描述

我必须处理相当大的XML文件，并且我想使用 xml-conduit 的流式API遍历它们并提取所需的信息.就我而言，使用流 xml-conduit 尤其吸引人，因为我不需要这些文件中的大量数据，而且我需要对其进行简单的聚合，因此管道是完美的.

I have to handle rather big XML files and I want to use the streaming API of xml-conduit to go through them and extract the info I need. In my case using streaming xml-conduit is especially appealing because I don't need much data from these files, and I need to perform simple aggregations on it so conduits are perfect.

现在，我并不总是知道文件的确切结构.文件是由世界各地不同版本的软件(有时是错误的软件)生成的，因此我无法强加该模式.

Now, I don't always know the exact structure of the file. Files are generated by different versions of (sometimes buggy) software around the world so I can't impose the schema.

但是，我知道我感兴趣的元素及其形状.但是，正如我所说，这些元素可以与其他元素等以不同的顺序放置.

I know, however, elements that I am interested in, and their shapes. But, as I said, these elements can be located in different order with other elements, etc.

我想，我需要的只是跳过我不感兴趣的所有元素，而只考虑需要的元素.

What I need, I guess, is just to skip all the elements I am not interested in and only to consider ones that want.

我最初想写这样的东西:

I initially wanted to write something like that:

tagName "person" (requireAttr "age" <* ignoreAttrs) <|> ignoreTag (const True)

但是它不会编译，因为 ignoreType 返回 Maybe()

but it wouldn't compile because ignoreType returns Maybe ()

使用 xml-conduit 流式API时跳过所有未知"标签的方法是什么?

What would be the way to skip all the "unknown" tags when using xml-conduit streaming API?

推荐答案

如建议的此处

λ> runConduit $ Text.XML.Stream.Parse.parseLBS def  "<foo>bar</foo><person age=\"25\">Michael</person><person age=\"2\">Eliezer</person>" .| many_ (choose [takeTree "person" ignoreAttrs, ignoreAnyTreeContent]) .| manyYield parsePerson .| Data.Conduit.List.consume 
[Person 25 "Michael",Person 2 "Eliezer"]

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