实参太多 [英] Too many arguments to function

查看:117
本文介绍了实参太多的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我从头文件中得到以下错误:太多参数无法使用void printCandidateReport(); .我对C ++相当陌生,只需要一些正确方向的指导即可解决此错误.

I am getting this error from my header file: too many arguments to function void printCandidateReport();. I am fairly new to C++ and just need some guidance in the right direction to solving this error.

我的头文件如下:

#ifndef CANDIDATE_H_INCLUDED
#define CANDIDATE_H_INCLUDED

// Max # of candidates permitted by this program
const int maxCandidates = 10;

// How many candidates in the national election?
int nCandidates;

// How many candidates in the primary for the state being processed
int nCandidatesInPrimary;

// Names of the candidates participating in this state's primary
extern std::string candidate[maxCandidates];

// Names of all candidates participating in the national election
std::string candidateNames[maxCandidates];

// How many votes wone by each candiate in this state's primary
int votesForCandidate[maxCandidates];

void readCandidates ();
void printCandidateReport ();
int findCandidate();
#endif

和调用此头文件的文件:

and the file calling this header file:

#include <iostream>
#include "candidate.h"
/**
* Find the candidate with the indicated name. Returns the array index
* for the candidate if found, nCandidates if it cannot be found.
*/
int findCandidate(std::string name) {
    int result = nCandidates;
    for (int i = 0; i < nCandidates && result == nCandidates; ++i)
        if (candidateNames[i] == name)
            result = i;
    return result;
}

/**
* Print the report line for the indicated candidate
*/
void printCandidateReport(int candidateNum) {
    int requiredToWin = (2 * totalDelegates + 2) / 3; // Note: the +2 rounds up
    if (delegatesWon[candidateNum] >= requiredToWin)
        cout << "* ";
    else
        cout << "  ";
    cout << delegatesWon[candidateNum] << " " << candidateNames[candidateNum]
         << endl;
}

/**
* read the list of candidate names, initializing their delegate counts to 0.
*/
void readCandidates() {
    cin >> nCandidates;
    string line;
    getline(cin, line);

    for (int i = 0; i < nCandidates; ++i) {
        getline(cin, candidateNames[i]);
        delegatesWon[i] = 0;
    }
}

为什么会出现此错误,我该如何解决?

why am I getting this error and how can I fix it?

推荐答案

在头文件中,您声明:

void printCandidateReport ();

但是在实现上是:

void printCandidateReport(int candidateNum){...}

将头文件更改为

void printCandidateReport(int candidateNum);

这篇关于实参太多的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆