仅包含一个#include-expression一次包含多个头文件吗? [英] Include multiple header-files at once with only one #include-expression?

问题描述

该语法是否有可能一次包含多个标头的表达式，而无需为每个新文件编写"#include"表达式?

Is there any expression possible for the syntax to include multiple headers at once, with no need to write the "#include"-expression for each file new?

例如，

#include <stdio.h>, <stdlib.h>, <curses.h>, <string.h>  /* Dummy-Expression 1. */

OR

#include <stdio.h> <stdlib.h> <curses.h> <string.h>     /* Dummy-Expression 2. */

问题是针对C AND C ++的.

Question is for C AND C++.

推荐答案

否，无法执行此操作.您必须将每个 #include 键入(或复制)到自己的行中，如下所示:

No, there is no way to do this. You have to type out (or copy) each #include to its own line, like this:

#include <stdio.h>
#include <stdlib.h>
#include <curses.h>
#include <string.h>

这适用于C和C ++.

This applies to both C and C++.

其他一些答案讨论了如何创建另一个包含每个头文件的头文件，但是我不打算讨论这样做.一般来说，这是一个坏主意，会导致名称空间污染以及更改该头文件时需要重新编译等问题.

Some of the other answers discuss creating another header file that includes each of these, but I'm not going to discuss doing that. It in general is a bad idea and causes issues like namespace pollution and the need to recompile when you change that header file.

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