htmlagilitypack通过名称获取元素的节点 [英] htmlagilitypack getting an element's node by the name

问题描述

如何通过名称获取元素的节点.有GetElementById，为什么没有GetElementByName.有问题的元素是:

How can I get the node of an element by the name. There is GetElementById, why no GetElementByName. The element in question is:

   <select class="box1" name="DAY" tabindex="31"> … </select>

我希望能够获得此节点.但是我不知道如何.

I want to be able to get this node. But I have no idea how.

Pete:请删除该问题已得到回答.完全错误，请自己尝试.node.Name不是属性'name'的名称，它不是我需要的标记名.

Pete: please remove that this question has been answered. It is totally WRONG go try it yourself. the node.Name is not the name of the attribute 'name' its the tagname which is NOT what I need.

推荐答案

您没有访问后代中"select"标签的名为"name"的节点属性.您正在使用标记的属性名称(xe.Name).正确的方法可以是:

You are not accessing the node attribute called "name" of the "select" tags in the descendants. You are using the property Name of the tag (xe.Name). The correct approach can be :

document.DocumentNode.Descendants("select").Where(node => node.GetAttributeValue("name", "").Equals("DAY", StringComparison.InvariantCultureIgnoreCase));

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