如何解决＆QUOT;未处理的异常类型ClassNotFoundException的＆QUOT;和＆QUOT; Vector是原始类型＆QUOT;错误？ [英] How to solve "Unhandled exception type ClassNotFoundException" and "Vector is a raw type" errors?

问题描述

在servlet的一面，我想收到来自applet发送的载体。在code是像

In servlet side, I am trying to receive an vector sent from the applet. The code is like

InputStream in = request.getInputStream();
ObjectInputStream inputFromApplet = new ObjectInputStream(in);
Vector v = (Vector) inputFromApplet.readObject();

但是，编译器指定下面一个是错的。

But the compiler specifies that the following one is wrong.

Vector v = (Vector) inputFromApplet.readObject();

该错误消息

在该行多个标记

  
• 未处理的异常类型的ClassNotFoundException

  
• Vector是原始类型。引用泛型类型矢量
     应参数

  
• Vector是原始类型。引用泛型类型矢量
     应参数

  

这有什么错我的code？谢谢你。

What's wrong with my code? Thanks.

推荐答案

有关外，包住code在

For the exception, wrap your code in

try {
   <your code here>
} catch (ClassNotFoundException e) {
   <code that happens when class can't be found>
}

其他的消息是警告，不会从编译停止程序。他们提到需要对parametrised类型的参数，坚持以新规格（如Java 1.5）。所以，如果你想存储整数向量，使用矢量＆lt;整数GT; 。这改变了整数，而不是普通的对象的方法，需要你通常会得到并增加类型安全性。

The other messages are warnings which won't stop your program from compiling. They refer to needing a parameter on parametrised types to adhere to new specifications (as of Java 1.5). So, if you want to store integers in a Vector, use Vector<Integer>. This changes the methods to requiring Integers instead of the generic Object you'd normally get and increases type-safeness.

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