Angular 7将文件内容作为多部分/表单数据发布 [英] Angular 7 Post file contents as multipart/form-data

问题描述

我想在字符串变量中提供要发布的内容.我要使用:

I have the content I want to POST available in a string variable. I want to use:

import { HttpClient } from '@angular/common/http'

...为了达到与以下相同的效果:

... in order to accomplish the same effect as:

curl -F "image=@blob.bin" someurl.com

...，其中我的字符串变量的内容可能是本地文件"blob.bin"中的内容.我不确定该怎么做，但是 无效:

... where the contents of my string variable would be what might be in a local file called `blob.bin. I'm not sure how to do it, but this doesn't work:

this.http.post('http://someurl.com', fileContents)

如何使用Angular 7和HttpClient服务获得这种效果?我没有要与之交互的实际HTML表单，我只有一些规定的二进制/字符串内容，我需要发布，好像是由看起来像这样的表单提交的(与上面的卷曲相同):

How do you get this effect using Angular 7 and the HttpClient service? I don't have an actual HTML form that I'm interacting with, I just have some prescribed binary / string content that I need to post as though it was submitted by a form that looks like (which is the same as what the curl above does):

<form method='POST' action='http://someurl.com' enctype='multipart/form-data'>
  <input type='file' name='update'>
  <input type='submit' value='Update'>
</form>

我敢肯定，只是在执行正确的咒语时遇到麻烦即可.

I'm sure it can be achieved, just having trouble performing the right incantations.

推荐答案

使用 FormData

const formData: FormData = new FormData();
formData.append('files', this.logo, this.logo.name);
this.http.post("upload", formData)

在示例中， this.logo 是一个 File 对象.您可以像这样从输入中获取文件对象:

In the example, this.logo is a File object. You can get the file object from your input like so:

<input (change)="handleLogoFileInput($event.target.files)" type="file" name="update />

并在组件文件中:

handleLogoFileInput(files: FileList) {
  this.logo = files[0];
}

这篇关于Angular 7将文件内容作为多部分/表单数据发布的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！