Codewars:蚱hopper-年级挑战书 [英] Codewars: Grasshopper - Grade book challenge

问题描述

这是解决方案盯着我盯着我，但我似乎找不到它的那些时候之一！因此，请耐心等待我. kata指令如下:

This is one of those times where the solution is staring me right in the face but I can't seem to find it! So please be patient with me. The kata instruction is the following:

完成该函数，以便找到传递给它的三个分数的平均值，并返回与该年级相关的字母值.

Complete the function so that it finds the mean of the three scores passed to it and returns the letter value associated with that grade.

Numerical Score       Letter Grade

90 <= score <= 100    'A'
80 <= score < 90      'B'
70 <= score < 80      'C'
60 <= score < 70      'D'
0 <= score < 60       'F'

测试值都在0到100之间.无需检查负值或大于100的值.

Tested values are all between 0 and 100. There is no need to check for negative values or values greater than 100.

这是我的解决方案:

function getGrade (s1, s2, s3) {
  var score = (s1 + s2 + s3) / 3;
  if (90 <= score && score >= 100) {
      return 'A';
  } else if (80 <= score && score > 90) {
    return 'B';
  } else if (70 <= score && score > 80) {
    return 'C';
  } else if (60 <= score && score > 70) {
    return 'D';
  } else if (0 <= score && score > 60) {
    return 'F';
  }
}

getGrade(5,40,93);
getGrade(30,85,96);
getGrade(92,70,40);

无法终生认清自己在做错什么.

Can't for the life of me figure out what I am doing wrong.

推荐答案

您的条件不正确，如果不需要，则不需要多次检查.将代码更改为此:

your conditions are wrong and you don't need multiple check in same if .Change your code to this:

function getGrade (s1, s2, s3) {
  var score = (s1 + s2 + s3) / 3;
  if (score >= 90 && score <= 100) {
      return 'A';
  } else if (score >= 80 ) {
    return 'B';
  } else if (score >= 70 ) {
    return 'C';
  } else if (score >= 60) {
    return 'D';
  } else{
    return 'F';
  }
}

console.log(getGrade(5,40,93));
console.log(getGrade(30,85,96));
console.log(getGrade(92,70,40));

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