没有其他Python的Elif-row [英] Elif-row without else python

问题描述

是否可以在 if 行的末尾编写 else ，只有在所有 if 语句都没有的情况下才执行是真的吗示例:

Is it possible to write an else at the end of an if-row which only gets executed if none of all the if statements are true? Example:

if foo==5:
    pass
if bar==5:
    pass
if foobar==5:
    pass
else:
    pass

在此示例中，如果 foobar 不是5，则执行else部分，但如果 foo ， bar 和 foobar 都不是5.(但是，如果所有语句为true，则必须执行所有语句.)

In this example, the else part gets executed if foobar isn't 5, but I want it to be executed if foo, bar and foobar aren't 5. (But, if all statements are true, all of them have to be executed.)

推荐答案

我认为在Python或任何其他语言中，没有任何过分优雅的方式可以做到这一点.您可以将值存储在列表中，但会混淆实际的测试条件，例如

I don't think there's any overly elegant way to do this in Python or any other language. You could store the values in a list but that would obfuscate the actual test ifs, e.g.

tests = [bar ==4, foo == 6, foobar == 8]

if tests[0] :
  # do a thing
if tests[1] :
  # Make a happy cheesecake
if tests[2] :
  # Oh, that's sad

if not True in tests :
  # Invade Paris

或者您可以设置跟踪标记

Or you could set a tracking flag

wereAnyTrue = False

if foo == 4 :
  # Do the washing
  wereAnyTrue = True
if bar == 6 :
  # Buy flowers for girlfriend
  wereAnyTrue = True

# ... etc

if not wereAnyTrue :
  # Eat pizza in underpants

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