Python运算符过滤器无效(Selenium) [英] Python operator filter dosen't work (Selenium)

问题描述

大家好，我想用硒&过滤掉一些instagram用户.python，目标是使所有用户关注的人数都多于关注者，但我不知道他为什么会返回相同的结果:

Hey guys I am trying to filtered a few instagram users with selenium & python, the goal is to following all user have more following than followers but i don't know why he return me same result:

此帐户的示例:

通常，他必须打印出我跟随者多于关注者"

Normaly it he must to print me "have more followers than following"

我的代码:

followers = []    #list of url users
for follower in followers:
    #Iterate into the list
    scrap_follower = browser.find_element_by_xpath('/html/body/div[1]/section/main/div/header/section/ul/li[2]/a/span').get_attribute("title")
    
    scrap_following = browser.find_element_by_xpath('/html/body/div[1]/section/main/div/header/section/ul/li[3]/a/span').text
    
    
    follower_count = int(scrap_follower)
    following_count = int(scrap_following)
    
    browser.get(follower)
    sleep(2)
    
    followButton = browser.find_element_by_css_selector('button')
    
    print(follower_count)
    print(following_count)     
    
    if follower_count == 0:
        pass
        print("0 followers")
        
        if follower_count > following_count :
            print("have more followers than following")
            pass
    else:
        print("eligible")
            #Go to follow

我的控制台日志返回:

感谢您的帮助:)

推荐答案

第二条 if 语句需要与第一个语句对齐，否则除非 if follower_count == 0，否则它将永远不会执行:条件得到满足.

Your second if statement needs to align with the first one otherwise it will never execute unless the if follower_count == 0: condition is met.

您的代码:

follower_count = 1500
following_count = 1000

print(follower_count)
print(following_count)     

if follower_count == 0:
    pass
    print("0 followers")
    
    if follower_count > following_count :
        print("have more followers than following")
        pass
else:
    print("eligible")

结果(不正确):

1500
1000
eligible

正确的代码(第二条 if 语句与第一条 if 语句对齐)

Correct code (2nd if statement aligned with first if statement)

follower_count = 1500
following_count = 1000

print(follower_count)
print(following_count)     

if follower_count == 0:
    pass
    print("0 followers")
    
if follower_count > following_count :
    print("have more followers than following")
    pass
else:
    print("eligible")

结果:

1500
1000
have more followers than following

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