PHP脚本，显示文件夹中的图像 [英] PHP script that shows the images in a folder

问题描述

这是一个显示文件夹中图像的脚本.但是，有什么办法可以让我首先显示最新的图像?而不是相反.

This is a script that shows images in a folder. But is there a way that I can show the latest image first? Instead of the other way around.

$images = glob('*.{gif,png,jpg,jpeg}', GLOB_BRACE); // formats to look for
$num_of_files = 2; // number of images to display

foreach($images as $image)
{
     $num_of_files--;

     if($num_of_files > -1) // this made me laugh when I wrote it
       echo "<b>".$image."</b><br>Created on ".date('D, d M y H:i:s', filemtime($image)) ."<br><img src="."'".$image."' style='width: 95%'"."><br><br>" ; // display images
     else
       break;
   }

推荐答案

您需要将图像放入数组中，然后按上次修改的顺序进行排序.

You need to put your images into an array and then sort by last modified.

类似这样的东西:

$imagesToSort = glob('*.{gif,png,jpg,jpeg}');
    usort($imagesToSort, function($a, $b) {
    return filemtime($a) < filemtime($b);
});

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