为什么我已经使用randint函数为它创建了一个对象，但为什么我声明的随机变量没有改变? [英] Why is the random variable I declared not changing even though I have created an object for it using randint function

问题描述

import random
ran = random.randint(000,999)

n = int(input("Enter Any Number = "))

list=[]

for i in range(n):
    list.append(ran)
    print(i,"----",list)

print(list)

推荐答案

randint()返回该范围内的随机值.但是调用该函数只会生成一次随机值.因此， ran 包含了调用函数的随机值.您永远不会覆盖 ran ，因此它不会改变.

randint() returns a random value within that range. But calling that function only generates the random value once. So ran contains whatever that random value was from where you called the function; you never overwrite ran so it doesn't change.

展望未来，我建议使用反勾号包围您的代码.此外，这是您应该使用google的一个问题，例如通过搜索"random randint()"来查看该函数的工作原理.

Going forward I suggest using the back ticks to surround your code. Additionally, this is a question you should use google for, e.g. by searching 'random randint()' to see how the function works.

看起来您现在已经格式化了代码块，所以很好.另一个注意事项是，您应避免将Python关键字(例如 list )用作变量名.这会覆盖Python关键字，如果您想在同一文件中使用各种Python内置函数，可能会很麻烦.

Looks like you formatted your code block now, so that's good. Another note is you should refrain from using Python keywords, such as list, for variable names. This overwrites the Python keyword which can be troublesome if you want to use various Python built-ins in the same file.

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