价值传递的Java小程序 [英] value passing in java applet
本文介绍了价值传递的Java小程序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我传递价值,Java小程序,但值快到那里空
我的JavaScript小应用程序的部署:
<脚本SRC =JavaScript的/ deployJava.js>< / SCRIPT>
<脚本>
VAR属性= {ID:'dynamictreeapplet',code:'jstojava.com.vaannila.utility.dynamicTreeApplet.class',宽:1000,高:1000};
VAR参数= {jnlp_href:./ appletjars / a.jnlp'};
deployJava.runApplet(属性,参数,'1.6');
< / SCRIPT>
我的JNLP
<?XML版本=1.0编码=UTF-8&GT?;
< JNLP规范=1.0+codeBase的=HTTP://本地主机:8080 / docRuleToolProtocol / appletjars /HREF =a.jnlp> <信息>
<标题> dynamictree< /标题>
<卖主GT;&Ashutosh说LT; /卖主GT;
< /信息> <资源>
< J2SE版本=1.5 +HREF =http://java.sun.com/products/autodl/j2se/>
<罐子HREF =dynamictree.jar主要=真/>
<罐子HREF =prefuse.jar主要=真/>
< /资源>
JavaScript来传递值:
函数showSelected(值){
警报(+价值,从给定的值);
VAR diseasename =价值;
警报(diseasename);
dynamictreeapplet.dieasenameen code = diseasename;
} <小程序,说明NAME =dynamictree主级=com.vaannila.utility.dynamicTreeAppletWIDTH =500HEIGHT =500>
< / applet的递减>
< / JNLP>
解决方案
修改
dynamictreeapplet.dieasenameen code = diseasename;
到
document.dynamictreeapplet.dieasenameen code = diseasename;
和可能dieasenameen code到diseasenameen code。
i am passing value in java applet but value is coming there as null
my javascript for applet deployment :
<script src="javascript/deployJava.js"></script>
<script>
var attributes = { id:'dynamictreeapplet', code:'jstojava.com.vaannila.utility.dynamicTreeApplet.class',width:1000,height:1000} ;
var parameters = {jnlp_href:'./appletjars/a.jnlp'} ;
deployJava.runApplet(attributes, parameters, '1.6');
</script>
My jnlp
<?xml version="1.0" encoding="UTF-8"?>
<jnlp spec="1.0+" codebase="http://localhost:8080/docRuleToolProtocol/appletjars/" href="a.jnlp">
<information>
<title>dynamictree</title>
<vendor>Ashutosh</vendor>
</information>
<resources>
<j2se version="1.5+" href="http://java.sun.com/products/autodl/j2se" />
<jar href="dynamictree.jar" main="true" />
<jar href="prefuse.jar" main="true" />
</resources>
javascript to pass value :
function showSelected(value){
alert("the value given from"+value);
var diseasename=value;
alert(diseasename);
dynamictreeapplet.dieasenameencode=diseasename;
}
<applet-desc name="dynamictree" main-class="com.vaannila.utility.dynamicTreeApplet" width="500" height="500">
</applet-desc>
</jnlp>
解决方案
Change
dynamictreeapplet.dieasenameencode=diseasename;
to
document.dynamictreeapplet.dieasenameencode=diseasename;
and probably dieasenameencode to diseasenameencode .
这篇关于价值传递的Java小程序的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文