sqlite,选择查询不起作用 [英] sqlite, select query doesn't work

查看:86
本文介绍了sqlite,选择查询不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

- (UserInfo*)getCurrentUserInfo:(NSString*)userName
{
    UserInfo *userInfo = [[UserInfo alloc]init];

    sqlite3 *database;
    sqlite3_stmt *selectstmt;
    NSLog(@"userName:%@",userName);
    if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {
        NSString *sqlString = [NSString stringWithFormat:@"SELECT USER_LEVEL FROM USER_INFO WHERE USER_NAME = '%@'" , userName];
        NSLog(@"getCurrentUserInfo:%@",sqlString);
        const char *SqlCommand = [sqlString UTF8String];
        if (sqlite3_prepare_v2(database, SqlCommand, -1, &selectstmt, NULL) == SQLITE_OK) {
            NSLog(@"success!");
            while (sqlite3_step(selectstmt) == SQLITE_ROW) {
                NSString *userInfoStr = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 0)];
                NSLog(@"select result:%@",userInfoStr);
            }
        }
        sqlite3_finalize(selectstmt);
    }
    sqlite3_close (database);
    return userInfo;
}

以下是我的日志输出:

2012-03-06 17:50:11.556 MagicWords[508:f803] userName:Tan
2012-03-06 17:50:11.557 MagicWords[508:f803] getCurrentUserInfo:SELECT USER_LEVEL FROM USER_INFO WHERE USER_NAME = 'Tan'

它不会显示成功",因此sqlite3_prepare_v2不会返回yes.但是我的数据库还可以:

It doesn't print "success",so sqlite3_prepare_v2 don't return yes.but my database is ok:

我找不到问题吗?

推荐答案

添加sqlite错误消息.它将深入了解内部发生的情况.如果有关数据库的所有信息都正确,请检查表名.

Add sqlite error message . It will give an insight of what is going on inside. If all about your database is correct ,check the table name.

UserInfo *userInfo = [[UserInfo alloc]init];

    sqlite3 *database;
    sqlite3_stmt *selectstmt;
    NSLog(@"userName:%@",userName);
    if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {
        NSString *sqlString = [NSString stringWithFormat:@"SELECT USER_LEVEL FROM USER_INFO WHERE USER_NAME = '%@'" , userName];
        NSLog(@"getCurrentUserInfo:%@",sqlString);
        const char *SqlCommand = [sqlString UTF8String];
        if (sqlite3_prepare_v2(database, SqlCommand, -1, &selectstmt, NULL) == SQLITE_OK) {
            NSLog(@"success!");
            while (sqlite3_step(selectstmt) == SQLITE_ROW) {
                NSString *userInfoStr = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 0)];
                NSLog(@"select result:%@",userInfoStr);
            }
        }
      //Add the error message here.
       else
        {

         NSLog(@"%s",sqlite3_errmsg(database));

        }
       ///////
        sqlite3_finalize(selectstmt);
    }
    sqlite3_close (database);
    return userInfo;

这篇关于sqlite,选择查询不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆