错误:找不到动作或结果没有为动作定义任何结果.部分和结果{"col1":"col1"，"col2":"col2"} [英] Error: Could not find action or result No result defined for action action.Part and result {"col1":"col1","col2":"col2"}

问题描述

我没有从服务器获得JSON类型数据的响应.

I'm not getting response as JSON type data from server.

我正在使用JSON插件.

I'm using JSON plugin.

jQuery( "#dialog-form" ).dialog({ 
    autoOpen: false,
    height: 500,
    width: 750,
    modal: true,
    buttons :{
        "Search" : function(){
            jQuery.ajax({type : 'POST',
            dataType : 'json',
             url : '<s:url action="part" method="finder" />',
         success : handledata})
        }
    }
});
var handledata = function(data)
{
    alert(data);
}

如果 dataType ='json'，我没有得到任何响应，但是如果我没有提及任何 dataType ，则得到了页面的HTML格式

If dataType = 'json' I am not getting any response, but if I don't mention any dataType, I'm getting the HTML format of the page.

public String list(){
    JSONObject jo = new JSONObject();
    try {
        Iterator it = findList.iterator();
        while(it.hasNext()){
             SearchResult part = (SearchResult) it.next();
             jo.put("col1",part.getcol1());
             jo.put("col2",part.getcol2());
        }
        log.debug("--------->:"+jo.toString());
    } catch (Exception e) {
        log.error(e);
    }
    return jo.toString();
}

struts.xml:

<package name="default" namespace="/ajax" extends="json-default">
  <action name="finder" 
       class="action.Part" method="finder" name="finder">
       <result type="json" />
  </action>
</package>

JSP页面:

<div id="dialog-form" >
    <form action="" id="channelfinder">
        <textarea id="products" name="prodnbr"<s:property value='prodNbr'/>   
    </form>
</div>

控制台错误:

org.apache.struts2.dispatcher.Dispatcher-无法找到操作或结果没有为操作action.Part定义结果.和结果{"col1":"col1"，"col2":"col2"}

org.apache.struts2.dispatcher.Dispatcher - Could not find action or result No result defined for action action.Part and result {"col1":"col1","col2":"col2"}

web.xml :

web.xml:

    <?xml version="1.0" encoding="ISO-8859-1"?>
     <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
      <display-name>/parts</display-name>
      <description>Parts List Web App</description>

    <filter>
          <filter-name>struts-cleanup</filter-name>
          <filter-class>org.apache.struts2.dispatcher.ActionContextCleanUp</filter-class>
        </filter>

        <filter>
        <filter-name>sitemesh</filter-name>
        <filter-class>com.opensymphony.module.sitemesh.filter.PageFilter</filter-class>
        </filter>

       <filter>
        <filter-name>struts2</filter-name>
        <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
        <init-param>
            <param-name>actionPackages</param-name>
            <param-value>com.action</param-value>
        </init-param>
    </filter>


    <filter-mapping>
        <filter-name>struts-cleanup</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <filter-mapping>
        <filter-name>sitemesh</filter-name>
        <url-pattern>/*</url-pattern>
        <dispatcher>REQUEST</dispatcher>
        <dispatcher>FORWARD</dispatcher>
        <dispatcher>INCLUDE</dispatcher>
    </filter-mapping>

    <filter-mapping>
        <filter-name>struts2</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
    <error-page>
        <exception-type>java.lang.Throwable</exception-type>
        <location>/errorPage.jsp</location>
    </error-page>
    <error-page>
        <error-code>404</error-code>
        <location>/errorPage.jsp</location>
    </error-page>

  <!-- Spring -->
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/applicationContext.xml</param-value>
  </context-param>
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>

  </web-app>

我没有获得有关jQuery成功的数据.请纠正我，这是怎么了?

I'm not getting data to jQuery success. Please correct me, whats wrong here?

推荐答案

dataType:'json'.ajax/"rel =" noreferrer> jQuery Ajax 指定执行操作和结果并从中返回响应时，预期 success 回调函数将返回的数据类型服务器.

A dataType : 'json' is used by jQuery Ajax to specify a data type that is expected to return by the success callback function when the action and result is executed, and a response returned from the server.

dataType (默认值:Intelligent Guess( xml ， json ， script 或 html ))

dataType (default: Intelligent Guess (xml, json, script, or html))

类型: String

期望从服务器返回的数据类型.如果未指定，则jQuery将尝试根据响应的MIME类型来推断它(XML MIME类型将产生XML，在1.4中，JSON将产生JavaScript对象，在1.4脚本中，脚本将执行该脚本，而其他任何内容将是返回为字符串).

The type of data that you're expecting back from the server. If none is specified, jQuery will try to infer it based on the MIME type of the response (an XML MIME type will yield XML, in 1.4 JSON will yield a JavaScript object, in 1.4 script will execute the script, and anything else will be returned as a string).

URL应该正确指向动作映射.假设它将在默认名称空间中，否则您应该修改URL和映射以添加 namespace attribute.

The URL should correctly point to the action mapping. Assume it will be in the default namespace, otherwise you should modify URL and mapping to add the namespace attribute.

<script type="text/javascript">
  $(function() {
    $("#dialog-form").dialog ({
      autoOpen: true,
      height: 500,
      width: 750,
      modal: true,
      buttons : {
        "Search" : function() {
          $.ajax({
            url : '<s:url action="part" />',
            success : function(data) {
              //var obj = $.parseJSON(data);
              var obj = data;
              alert(JSON.stringify(obj));
            }
          });
        }
      }
    });
  });
</script>

如果手动构建 JSONObject ，则不需要

返回 json 结果类型.您可以将文本作为流结果返回，然后根据需要将字符串转换为JSON

Returning json result type is not needed if you build the JSONObject manually. You can return text as stream result then convert a string to JSON if needed.

struts.xml :

struts.xml:

<package name="default" extends="struts-default">
  <action name="part" class="action.PartAction" method="finder">    
    <result type="stream">
      <param name="contentType">text/html</param>
      <param name="inputName">stream</param>
    </result>
  </action>
</package>

操作:

public class PartAction extends ActionSupport {

  public class SearchResult {
    private String col1;
    private String col2;

    public String getCol1() {
      return col1;
    }

    public void setCol1(String col1) {
      this.col1 = col1;
    }

    public String getCol2() {
      return col2;
    }

    public void setCol2(String col2) {
      this.col2 = col2;
    }

    public SearchResult(String col1, String col2) {
      this.col1 = col1;
      this.col2 = col2;
    }
  }

  private InputStream stream;

  //getter here
  public InputStream getStream() {
    return stream;
  }

  private List<SearchResult> findList = new ArrayList<>();

  public List<SearchResult> getFindList() {
    return findList;
  }

  public void setFindList(List<SearchResult> findList) {
    this.findList = findList;
  }

  private String list() {
    JSONObject jo = new JSONObject();
    try {
      for (SearchResult part : findList) {
        jo.put("col1", part.getCol1());
        jo.put("col2", part.getCol2());
      }
      System.out.println("--------->:"+jo.toString());
    } catch (Exception e) {
      e.printStackTrace();
      System.out.println(e.getMessage());
    }
    return jo.toString();
  }

  @Action(value="part", results = {
    @Result(name="stream", type="stream", params = {"contentType", "text/html", "inputName", "stream"}),
    @Result(name="stream2", type="stream", params = {"contentType", "application/json", "inputName", "stream"}),
    @Result(name="json", type="json", params={"root", "findList"})
  })
  public String finder() {
    findList.add(new SearchResult("val1", "val2"));
    stream = new ByteArrayInputStream(list().getBytes());
    return "stream2";
  }
}

我对结果类型和内容类型放置了不同的结果，以更好地描述这个想法.您可以返回任何这些结果，并返回带或不带字符串的JSON对象.字符串化版本需要解析返回的数据以获得JSON对象.您还可以选择哪种序列类型更好地进行序列化以满足您的需要，但我的目标是表明，如果需要序列化简单对象，则无需json插件即可使其工作.

I have placed different results with result type and content type to better describe the idea. You could return any of these results and return JSON object either stringified or not. The stringified version requires to parse returned data to get the JSON object. You can also choose which result type better serializes to suit your needs but my goal was to show that if you need to serialize the simple object then json plugin is not necessary to get it working.

参考:

• 我们如何返回文本字符串作为响应
  
• 如何转换 JSONObject 字符串

这篇关于错误:找不到动作或结果没有为动作定义任何结果.部分和结果{"col1":"col1"，"col2":"col2"}的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！