初学者数字合成器 [英] Beginner Digital Synth

问题描述

我正在研究用Java编写音频合成器，并且想知道是否有人对编写这样的程序有任何建议或良好的资源.我正在寻找有关生成原始声波，如何将其输出为可用形式(通过扬声器播放)以及有关该主题的一般理论的信息.谢谢大家.

I'm looking into writing a audio syntesizer in Java, and was wondering if anybody has any advice or good resources for writing such a program. I'm looking for info on generating raw sound waves, how to output them into a usable form (playing over speakers), as well as general theory on the topic. Thanks guys.

推荐答案

1. 此问题基本上与将函数映射到数字数组有关.支持一流功能的语言在这里非常有用.

1. This problem is basically about mapping functions to arrays of numbers. A language that supports first-class functions would come in really handy here.

退房 http://www.harmony-central.com/Computer/Programming 和 http://www.developer.com/java/other/article.php/3071021 获取一些与Java有关的信息.

Check out http://www.harmony-central.com/Computer/Programming and http://www.developer.com/java/other/article.php/3071021 for some Java-related info.

如果您不了解编码声音数据的基本概念，请阅读 http://en.wikipedia.org/wiki/Sampling_rate

If you don't know the basic concepts of encoding sound data, then read http://en.wikipedia.org/wiki/Sampling_rate

规范的WAVE格式非常简单，请参见 http://www.lightlink.com/tjweber/StripWav/Canon.html .标头(前44个字节)+ wave数据.您不需要任何库即可实现.

The canonical WAVE format is very simple, see http://www.lightlink.com/tjweber/StripWav/Canon.html. A header (first 44 bytes) + the wave-data. You don't need any library to implement that.

在C/C ++中，相应的数据结构如下所示:

In C/C++, the corresponding data structure would look something like this:

typedef struct _WAVstruct
{
    char headertag[4];
    unsigned int remnantlength;
    char fileid[4];

    char fmtchunktag[4];
    unsigned int fmtlength;
    unsigned short fmttag;
    unsigned short channels;
    unsigned int samplerate;
    unsigned int bypse;
    unsigned short ba;
    unsigned short bipsa;

    char datatag[4];
    unsigned int datalength;

    void* data; //<--- that's where the raw sound-data goes
}* WAVstruct;

我不确定Java.我想您必须将结构"替换为类"，将"void *数据"替换为"char []数据"或"short []数据"或"int []数据"，这对应于每位的位数样本，如bipsa字段中所定义.

I'm not sure about Java. I guess you'll have to substitute "struct" with "class" and "void* data" with "char[] data" or "short[] data" or "int[] data", corresponding to the number of bits per sample, as defined in the field bipsa.

要在其中填充数据，您可以在C/C ++中使用类似的东西:

To fill it with data, you would use something like that in C/C++:

int data2WAVstruct(unsigned short channels, unsigned short bipsa, unsigned int samplerate, unsigned int datalength, void* data, WAVstruct result)
{
    result->headertag[0] = 'R';
    result->headertag[1] = 'I';
    result->headertag[2] = 'F';
    result->headertag[3] = 'F';
    result->remnantlength = 44 + datalength - 8;
    result->fileid[0] = 'W';
    result->fileid[1] = 'A';
    result->fileid[2] = 'V';
    result->fileid[3] = 'E';

    result->fmtchunktag[0] = 'f';
    result->fmtchunktag[1] = 'm'; 
    result->fmtchunktag[2] = 't';
    result->fmtchunktag[3] = ' ';
    result->fmtlength = 0x00000010;
    result->fmttag = 1;
    result->channels = channels;
    result->samplerate = samplerate;
    result->bipsa = bipsa;
    result->ba = channels*bipsa / 8;
    result->bypse = samplerate*result->ba;

    result->datatag[0] = 'd';
    result->datatag[1] = 'a';
    result->datatag[2] = 't';
    result->datatag[3] = 'a';
    result->datalength = datalength;

    result->data = data; // <--- that's were the data comes in

    return 0; // an error code, not implemented, yet ...; in Java: return result
}

同样，我不确定Java，但是如果将空指针转换为与比特率相对应的数组，则转换应该很简单.

Again, I'm not sure about Java but the conversion should be straightforward if you convert the void-pointer to an array corresponding to the bitrate.

然后只需将整个结构写入文件即可获得可播放的wave文件.

Then simply write the entire structure to a file to get a playable wave file.

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