Java如何选择要使用的构造函数? [英] How does Java choose which constructor to use?

问题描述

我无法理解以下程序的输出.

I am not able to understand the output of the following program.

public class Confusing {

    private Confusing(Object o) {
        System.out.println("Object");
    }

    private Confusing(double[] dArray) {
        System.out.println("double array");
    }

    public static void main(String[] args) {
        new Confusing(null);
    }
}

正确的输出是双数组".当两者都可以接受null时，为什么选择此构造函数比其他构造函数更具体?

The correct output is "double array". WHy was this constructor chosen as more specific than the other when both can accept null?

推荐答案

即使两个构造函数都可以接受 null ， double [] 继承来自 java.lang.Object ，因此更加具体.

Even though both constructors can accept null, double[] inherits from java.lang.Object, and is therefore more specific.

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