字符串的CharAt方法使用long [英] String's CharAt method using long

问题描述

我想在非常大的字符串的特定位置找到字符.但是我无法使用 charAt()方法，因为该范围超出了int的范围.有什么调整吗?

I want to find the character at a particular position of a very large string. However i am unable to use charAt() method because the range exceeds that of int. Is there a tweak to this?

推荐答案

在Java中，字符串由字符数组支持.数组的理论大小受 int 的最大值限制，因此不可能有超过2个 ³¹ -1个字符的String开头.

In Java, Strings are backed by a character array. The theoretical size of an array is limited by the maximum value of int, so it's impossible to have a String with over 2³¹-1 characters to begin with.

要解决此问题，您可以创建自己的使用多个数组或字符串作为存储空间的字符串类.

To overcome this issue you can create a string class of your own that uses multiple arrays or strings as storage.

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