在Java中查找字符串的所有大写字母 [英] Finding all uppercase letters of a string in java
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问题描述
所以我试图在用户输入的字符串中查找所有大写字母,但我不断遇到此运行时错误:
So I'm trying to find all the uppercase letters in a string put in by the user but I keep getting this runtime error:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException:
String index out of range: 4
at java.lang.String.charAt(String.java:686)
at P43.main(P43.java:13)
I feel foolish but I just can't figure this out and oracle even talks about charAt on the page about java.lang.StringIndexOutOfBoundsException
这是我的代码,用于查找大写字母并打印它们:
Here is my code for finding the uppercase letters and printing them:
import java.io.*;
import java.util.*;
public class P43{
public static void main(String[] args){
Scanner in = new Scanner(System.in);
//Uppercase
String isUp = "";
System.out.print("Please give a string: ");
String x = in.next();
int z = x.length();
for(int y = 0; y <= z; y++){
if(Character.isUpperCase(x.charAt(y))){
char w = x.charAt(y);
isUp = isUp + w + " ";
}
}
System.out.println("The uppercase characters are " + isUp);
//Uppercase
}
}
我非常感谢您的投入和帮助.
I'd really appreciate any input and or help.
推荐答案
for(int y = 0; y <= z; y++){
应该是
for(int y = 0; y < z; y++){
记住数组索引从零开始.
Remember array index starts from ZERO.
字符串长度返回
字符串中16位Unicode字符的数量
the number of 16-bit Unicode characters in the string
由于循环从零开始,因此循环应以长度1终止.
Because loop started from ZERO, loop should terminate at length-1.
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