将数字的所有数字加起来并用Java分别显示数字 [英] Sum all digits of a number and show the digits separately in Java

问题描述

我已经使用了很多这个网站，但是我从未真正写过任何东西.今天，我偶然发现了一个我似乎找不到的解决方案.

问题在于，我有一个 int变量，其位数未知.要求我对所有这些数字求和，然后打印/显示所有数字并分开显示.

例如，用户输入数字"12345678"，最后我需要显示一条消息，说数字1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36".我知道如何将所有这些数字分开并求和，但是我不知道如何保存每个数字然后将其显示出来，因为我不仅不知道正确的数字量，而且我也不知道它们的值要么.

通常这并非难事，但这对我来说是棘手的部分，因为我们还没有学过诸如 arrays ， strings ，索引，等等，我们不允许使用它们.因此，我应该使用最简单的代码来做到这一点.

到目前为止，我有以下内容:

  import java.util.Scanner;公共课程编号{公共静态void main(String [] args){整数，结果；扫描仪sc =新的扫描仪(System.in);System.out.println(输入数字:");数字= sc.nextInt();结果= 0;而(数字> 0){结果=结果+(数字％10);数字=数字/10;}System.out.println(这是消息要去的地方.");}} 

解决方案

 静态最终Scanner输入= new Scanner(System.in);公共静态void main(String [] args){整数，结果；System.out.println(输入数字:");数字= input.nextInt();结果= 0;System.out.print(数字:");//倒数int reversedNum = 0;while(数字！= 0){reversedNum = reversedNum * 10 +数字％10;数字=数字/10;}//遍历数字并打印出来while(reversedNum> 0){System.out.print((reversedNum％10));结果=结果+(倒数％10);reversedNum = reversedNum/10;如果(reversedNum> 0){System.out.print("+");}}System.out.println("=" +结果);} 

这可以按正确的顺序打印出所有数字，而无需使用数组和字符串.

示例:

 输入数字:12345数字:1 + 2 + 3 + 4 + 5 = 15成功构建(总时间:5秒) 

I've been using this site quite a lot but I've never really wrote anything. Today, I've stumbled upon a problem which solution I can't seem to find.

The problem is that, I have an int variable with an unknown number of digits. It is asked of me to sum all of those digits and then have it printed/shown_as_a_message with all those digit separated.

For example, the user enters the number "12345678" and in the end I need to have a message saying "The numbers 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36". I know how to separate and sum all of those numbers, but I don't know how to save each number and then have it shown, because not only do I not know the right amount of digits, but I don't know their values either.

Usually that wouldn't be hard to do, but here comes the tricky part for me, since we haven't learned things like arrays, strings, indexes, etc., we're not allowed to use them. So, I'm supposed to do it with the simplest type of code possible.

So far, I've got the following:

import java.util.Scanner;
public class Numbers {
    public static void main(String[] args) {
        int number, result;
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter number:");
        number = sc.nextInt();
        result = 0;
        while (number > 0){
            result = result + (number % 10);
            number = number / 10;
        }
        System.out.println("This is where the message would go.");
    }
}

解决方案

static final Scanner input = new Scanner(System.in);

public static void main(String[] args) {
    int number, result;
    System.out.println("Enter number:");
    number = input.nextInt();
    result = 0;
    System.out.print("The numbers: ");

    //Reverses the number
    int reversedNum = 0;
    while (number != 0) {
        reversedNum = reversedNum * 10 + number % 10;
        number = number / 10;
    }

    //Iterates over the number and prints it out
    while (reversedNum > 0) {
        System.out.print((reversedNum % 10));

        result = result + (reversedNum % 10);
        reversedNum = reversedNum / 10;

        if (reversedNum > 0) {
            System.out.print(" + ");
        }
    }
    System.out.println(" = " + result);
}

This works to print out all the numbers in the correct order without using arrays and strings.

Example:

Enter number:
12345
The numbers: 1 + 2 + 3 + 4 + 5 = 15
BUILD SUCCESSFUL (total time: 5 seconds)

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