如何在百里香中处理和连接琴弦 [英] How to process and join string in thymeleaf

问题描述

我有一个字符串列表-这些是我感兴趣的属性名称:我想加入这些字符串的值，但不使用属性名称，而是使用它们的属性值.我看到起点是#strings.listJoin -但是如何说要使列表中的元素与属性文件中的值相匹配?

I have a list of strings - which are the properties names that I am interested in: I want to join the values of these strings, but not using the properties name, but the properties values for them. I saw that the starting point is #strings.listJoin - but how can I say to match the elements in the list against their value in the properties files?

列表将是: [名称，地址] ，并且在属性文件中，我具有:

The list would be: [name, address] and in the properties file I have:

name=stg
address=another something

我想获取字符串: stg，另一个东西

推荐答案

您可以使用#messages.listMsg 和#strings.listJoin

具有从您的@Controller返回的模型:

Having the model returned from your @Controller:

model.addAttribute("messageKeyList", Lists.newArrayList("name", "address"));

您可以像这样加入翻译后的邮件列表:

You can join list of translated messages like this:

<div th:text="${#strings.listJoin(#messages.listMsg(messageKeyList), ',')}"></div>

应该达到您期望的目标，例如:

Which should produce what you expect, e.g.:

Some name,Some address

名称和地址是邮件文件中的键.

Where name and address are keys in your messages file.

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