如何在忽略括号的部分时拆分​​字符串? [英] How to split string while ignoring portion in parentheses?

问题描述

我有一个字符串，我想通过使用逗号作为分隔符将其拆分为一个数组.我不希望括号中的字符串部分被分割，即使它们包含逗号也是如此.

I have a string that I want to split into an array by using the commas as delimiters. I do not want the portions of the string that is between parentheses to be split though even if they contain commas.

例如:

"bibendum, morbi, non, quam (nec, dui, luctus), rutrum, nulla" 

应成为:

["bibendum", "morbi", "non", "quam (nec, dui, luctus)", "rutrum", "nulla"]

但是当我使用基本的 .split(，")时，它将返回:

But when I use a basic .split(","), it returns:

["bibendum", " morbi", " non", " quam (nec", " dui", " luctus)", " rutrum", " nulla"]

我需要它返回:

["bibendum", " morbi", " non", " quam (nec, dui, luctus)", " rutrum", " nulla"]

我们非常感谢您的帮助.

Your help is appreciated.

推荐答案

与其专注于您不想要的，通常更容易将正则表达式表达为想要的，并 match ，并带有全局正则表达式:

Instead of focusing on what you do not want it's often easier to express as a regular expression what you want, and to match that with a global regex:

var str = "bibendum, morbi, non, quam (nec, dui, luctus), rutrum, nulla";
str.match(/[^,]+(?:\(+*?\))?/g) // the simple one
str.match(/[^,\s]+(?:\s+\([^)]*\))?/g) // not matching whitespaces

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