使用正则表达式获取括号内的字符串，删除括号 [英] Get string inside parentheses, removing parentheses, with regex

问题描述

我有这两个字符串...

I have these two strings...

var str1 = "this is (1) test";
var str2 = "this is (2) test";

并且想要编写一个RegEx来提取括号内的内容，如"1" 和"2" 一样，以产生如下所示的字符串.

And want to write a RegEx to extract what is INSIDE the parentheses as in "1" and "2" to produce a string like below.

var str3 = "12";

现在我有这个正则表达式，它也返回括号...

right now I have this regex which is returning the parentheses too...

var re = (/\((.*?)\)/g);

var str1 = str1.match(/\((.*?)\)/g);
var str2 = str2.match(/\((.*?)\)/g);

var str3 = str1+str2; //produces "(1)(2)"

推荐答案

类似

JavaScript

Javascript

var str1 = "this is (1) test",
    str2 = "this is (2) test",
    str3 = str1.match(/\((.*?)\)/)[1] + str2.match(/\((.*?)\)/)[1];

alert(str3);

在 jsfiddle

请参见

(x)匹配x并记住匹配.这些称为捕获括号.

(x) Matches x and remembers the match. These are called capturing parentheses.

例如，/(foo)/匹配并记住"foo bar"中的"foo".这可以从结果数组的元素中调用匹配的子字符串 1 ，...，[n]或来自预定义的RegExp对象的属性$ 1，...，9美元.

For example, /(foo)/ matches and remembers 'foo' in "foo bar." The matched substring can be recalled from the resulting array's elements 1, ..., [n] or from the predefined RegExp object's properties $1, ..., $9.

捕获组的性能会受到影响.如果您不需要要调用的匹配子字符串，更喜欢使用非捕获括号(请参见下文).

Capturing groups have a performance penalty. If you don't need the matched substring to be recalled, prefer non-capturing parentheses (see below).

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