正则表达式以匹配没有连续空格的用户名 [英] regex to match a username with no consecutive spaces

问题描述

我正在努力使javascript正则表达式满足以下要求:

I am struggling to make a javascript regex to satisfy the following:

1. 第一个字符必须为字母( [a-zA-Z] )
2. 其余的可以是任何字母，任何数字，连字符，点，下划线和空格
3. 但不能连续使用空格，，例如:连续两个或多个空格
4. 长度必须在3到25(含)之间

1. The first character has to be alphabetical ([a-zA-Z])
2. The rest can be any letters, any numbers, hyphen, dot, underscore and spaces
3. BUT no consecutive spaces, e.g: two or more spaces in a row
4. The length has to be between 3 and 25 (inclusive)

这就是我发现的正则表达式:

/^[a-z][\s\w.-]{3,24}$/i

我当前的正则表达式可以运行，但是无法测试用户是否已写出连续的空格.我该如何测试?

My current regex works, but won't be able to test whether the user has written consecutive spaces. How can I test for that?

推荐答案

这应该对您有用:

/^[a-z](?!.* {2})[ \w.-]{2,24}$/gmi

RegEx演示

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