危险地渲染内容时如何使用React链接? [英] How to use React links when rendering content with dangerouslySetInnerHtml?

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本文介绍了危险地渲染内容时如何使用React链接?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

因此,我正在为React应用程序开发一个博客页面.该页面正在从CMS加载数据,并且博客文章的内容是原始html,我在页面上使用以下内容呈现:

So I'm developing a blog page for a react application. The page is loading data from a CMS and the content of the blog post is raw html which I render on the page with:

< div危险地设置InnerHTML = {{____:this.state.content}}/>

但是我张贴在帖子中的任何链接< a href ='/'>首页</a> 不使用react router,而是触发重新加载页面.

However any links I put in the post like <a href='/'>Home Page</a> don't use react router and instead trigger reloading the page.

有没有一种方法可以解决此问题,而不必解析HTML并用< Link> 替换< a> 标记?

Is there a way to handle this in react without having to parse the HTML and replace <a> tags with <Link>?

推荐答案

您可以在HTML容器上使用点击处理程序来捕获点击.如果点击来自< a> 标记(或其子级),则可以阻止默认设置,并使用 href .

You can use a click handler on the HTML container to catch clicks. If the click originates from an <a> tag (or a childrn of), you can prevent default, and use the href.

在这种情况下,您可以使用react-router的 withRouter 获取 history 对象,并使用 push 方法通知路由器.您还可以编辑该URL,或以其他方式对其进行操作.

In this case, you can use react-router's withRouter to get the history object, and to use the push method to notify the router. You can also edit the url, or manipulate it in other ways.

示例(使用代码时取消注释并删除控制台):

Example (uncomment and remove the console when you use the code):

// import { withRouter } from 'react-router-dom'

class HTMLContent extends React.Component {
  contentClickHandler = (e) => {
    const targetLink = e.target.closest('a');
    if(!targetLink) return;
    e.preventDefault();
    
    console.log(targetLink.href); // this.props.history.push(e.target.href)
  };
  
  render() {
    return (
      <div 
        onClick={this.contentClickHandler}
        dangerouslySetInnerHTML={{__html: this.props.content}} 
      />
    );
  }
}

// export default withRouter(HTMLContent);

const content = `<div>
  <a href="http://www.first-link.com">Link 1</a>
  <a href="http://www.second-link.com"><span>Link 2</span></a>
</div>`;

ReactDOM.render(
  <HTMLContent content={content} />,
  demo
);

<script crossorigin src="https://unpkg.com/react@16/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@16/umd/react-dom.development.js"></script>

<div id="demo"></div>

这篇关于危险地渲染内容时如何使用React链接?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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