合并具有相同键的两个对象数组,某些对象是否具有相同的值? [英] Merge two array of objects with same keys, some object won't have the same value?
问题描述
我想合并两个对象数组.键是相同的,但值可能并不总是相同.
I want to merge two arrays of objects. The keys are the same but the values might not always be the same.
最好在javascript中赞赏任何解决方案,但是python解决方案也可以.
Any solution is appreciated preferably in javascript, but a python solution is fine as well.
以下是示例数据:
Here is the sample data:
var g= [
{ id: 36, name: 'AAA', goal: 'yes' , 'random':27},
{ id: 40, name: 'BBB', goal: 'yes' },
{ id: 39, name: 'JJJ', goal: 'yes' },
{ id: 27, name: 'CCC', goal: 'yes' , lag: "23.3343"}];
var c= [
{ id: 36, name: 'AAA', goal: 'yes', color:"purple" },
{ id: 40, name: 'BBB', circle: 'yes', color:"purple" },
{ id: 100, name: 'JJJ', circle: 'yes'} ];
我的预期输出应该是:
var finalData = [{
{ id: 36, name: 'AAA', goal: 'yes' ,'random':27, color:"purple"},
{ id: 40, name: 'BBB', circle: 'yes', color:"purple"},
{ id: 39, name: 'JJJ', goal: 'yes' },
{ id: 27, name: 'CCC', goal: 'yes' ,lag: "23.3343"},
{ id: 100, name: 'JJJ', circle: 'yes' }
}]
这是我当前的代码,在某种程度上可以正常工作,但是没有添加可能遗漏的键.
Here is my current code, it works to some degree but it doesn't add keys it might have missed.
var finalData = [];
for(var i in g){
var shared = false;
for (var j in c)
if (c[j].name == g[i].name) {
shared = true;
break;
}
if(!shared) finalData.push(g[i])
}
finalData = finalData.concat(c);
finalData
推荐答案
您可以使用id .org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Object/assign"rel =" nofollow noreferrer> Object.assign
来创建独立的对象.
You could use a Map
for keeping same id
in the same object and Object.assign
for creating independent objects.
var g = [{ id: 36, name: 'AAA', goal: 'yes', 'random': 27 }, { id: 40, name: 'BBB', goal: 'yes' }, { id: 39, name: 'JJJ', goal: 'yes' }, { id: 27, name: 'CCC', goal: 'yes', lag: "23.3343" }],
c = [{ id: 36, name: 'AAA', goal: 'yes', color: "purple" }, { id: 40, name: 'BBB', circle: 'yes', color: "purple" }, { id: 100, name: 'JJJ', circle: 'yes' }],
map = new Map,
result = g.concat(c).reduce(function (r, o) {
var temp;
if (map.has(o.id)) {
Object.assign(map.get(o.id), o);
} else {
temp = Object.assign({}, o);
map.set(temp.id, temp);
r.push(temp);
}
return r;
}, []);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
没有reduce和concat的版本.
Version without reduce and without concat.
function merge(o) {
var temp;
if (map.has(o.id)) {
Object.assign(map.get(o.id), o);
return;
}
temp = Object.assign({}, o);
map.set(temp.id, temp);
result.push(temp);
}
var g = [{ id: 36, name: 'AAA', goal: 'yes', 'random': 27 }, { id: 40, name: 'BBB', goal: 'yes' }, { id: 39, name: 'JJJ', goal: 'yes' }, { id: 27, name: 'CCC', goal: 'yes', lag: "23.3343" }],
c = [{ id: 36, name: 'AAA', goal: 'yes', color: "purple" }, { id: 40, name: 'BBB', circle: 'yes', color: "purple" }, { id: 100, name: 'JJJ', circle: 'yes' }],
map = new Map,
result = [];
[g, c].forEach(function (a) {
a.forEach(merge);
});
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
使用动态键.
function mergeBy(key, data) {
return Array.from(data
.reduce((m, o) => m.set(o[key], { ...m.get(o[key]), ...o }), new Map)
.values()
);
}
var g = [{ id: 36, name: 'AAA', goal: 'yes', 'random': 27 }, { id: 40, name: 'BBB', goal: 'yes' }, { id: 39, name: 'JJJ', goal: 'yes' }, { id: 27, name: 'CCC', goal: 'yes', lag: "23.3343" }],
c = [{ id: 36, name: 'AAA', goal: 'yes', color: "purple" }, { id: 40, name: 'BBB', circle: 'yes', color: "purple" }, { id: 100, name: 'JJJ', circle: 'yes' }],
result = mergeBy('id', [...g, ...c]);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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