正则表达式，最多可匹配2个小数位的数字 [英] Regex that matches numeric with up to 2 decimal places

问题描述

我正在寻找一个正则表达式，它将匹配数字值和最多用户定义的小数位数.目前我有

I am after a regex that will match numeric values with up to a user defined number of decimal places. Currently I have

/(^-?\d\d*\.\d*$)|(^-?\d\d*$)|(^-?\.\d\d*$)/

这将允许输入尽可能多的位置，但我也想有时允许2表示货币或4或更多表示其他输入.我正在构建的功能是

which will allow as many places as input but I would also like to sometimes allow 2 for currency or 4 or more for other input. The function I am building is

var isNumeric = function(val, decimals) {
    // decimals is not used yet
    var objRegExp = /(^-?\d\d*\.\d*$)|(^-?\d\d*$)|(^-?\.\d\d*$)/;
    return objRegExp.test(val);
};

推荐答案

/^\s*-?[1-9]\d*(\.\d{1,2})?\s*$/

宽恕空格(\ s)是很好的.以上不允许从零开始.如果要允许的话:

It's good to be forgiving of whitespace (\s). The above doesn't allow starting with zero. If you want to allow that:

/^\s*-?\d+(\.\d{1,2})?\s*$/

以上两种方法均不允许小数点后没有小数点.如果要允许的话:

Neither of the above allow a decimal number with nothing before the decimal place. If you want to allow that:

/^\s*-?(\d+(\.\d{1,2})?|\.\d{1,2})\s*$/

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