已用对象断言调用 [英] Has been called with object assertion
问题描述
我正在监视的功能,接收对象作为参数.我需要断言该函数是用对象的某些属性调用的.
Function I'm spying on, receives object as an argument. I need to assert that the function been called with certain properties of the object.
例如:我的SUT具有:
e.g: my SUT has:
function kaboom() {
fn({
foo: 'foo',
bar: 'bar',
zap: function() { ... },
dap: true
});
}
在我的测试中,我可以这样做:
and in my test I can do this:
fnStub = sinon.stub();
kaboom();
expect(fnStub).to.have.been.called;
并且有效(很高兴知道 fn
被调用了).现在,我需要确保正确的对象已传递到函数中.我只关心 foo
和 bar
属性,即我必须为参数的特定属性设置匹配项.怎么样?
and that works (it's good to know that fn
's been called). Now I need to make sure that the right object has been passed into the function. I care about only foo
and bar
properties, i.e. I have to set match for specific properties of the argument. How?
upd:sinon.match()似乎适用于简单对象.让我们提高标准吧?
upd: sinon.match() seems to work for simple objects. Let's raise the bar, shall we?
如果我想在断言中包含 zap
函数怎么办?我该如何工作?
What if I want to include zap
function into assertion? How do I make that work?
推荐答案
假设您使用的是 sinon-chai ,您可以与 sinon.match 一起使用 namedWith
来实现这一目标
Assuming you're using sinon-chai, you can use calledWith
along with sinon.match to achieve this
expect(fnStub).to.have.been.calledWith(sinon.match({
foo: 'foo',
bar: 'bar'
}));
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