RegExp获取以冒号分隔的键值对中的文本 [英] RegExp to get text in a key value pair separated by a colon

问题描述

我在这里有我的Regexp示例: https://regex101.com/r/kE9mZ7/1

I have my Regexp example here: https://regex101.com/r/kE9mZ7/1

对于以下字符串:

key_1:一些文本，可能是逗号，以分号结尾；key_2:可能没有结尾分号的文本，但可能是

key_1: some text, maybe a comma, ending in a semicolon; key_2: text with possibly no ending semicolon, but could be

我想做以下事情:

var regEx_attrVal = /[\w :].*?(?=;|$)/g;
var results = attrs.match(regEx_attrVal);
      for(i=0;i<results.length;++i) {
        var split = results[i].split(':');

        preColon = split[0].trim();
        postColon = split[1].trim();

        //log preColon and postColon to console

      }

最终结果应该类似于:

//results[0]
preColon: key_1
postColon: some text, maybe a comma, ending in a semicolon

//results[1]
preColon: key_2
postColon: text with possibly no ending semicolon, but could be

我的正则表达式肯定是错误的，希望SO社区可以提供帮助！

My regexp is definitely wrong, hoping the SO community can help!

谢谢！

推荐答案

以下是提取这些值的正则表达式方法:

Here is a regex way to extract those values:

/(\w+):\s*([^;]*)/gi

或(因为标识符应以 _ 或字母开头):

or (as identifiers should begin with _ or a letter):

/([_a-z]\w*):\s*([^;]*)/gi

这是一个 regex演示

var re = /([_a-z]\w*):\s*([^;]*)/gi; 
var str = 'key_1: some text, maybe a comma, ending in a semicolon; key_2: text with no ending semicolon';
while ((m = re.exec(str)) !== null) {
    document.body.innerHTML += m[1] + ": " + m[2] + "<br/>";
}

模式详细信息:

• ([_ a-z] \ w *)-第1组匹配的标识符以 _ 或字母开头，后跟0+字母数字/下划线符号
• :-冒号
• \ s * -0+空格
• ([[^;] *)-0 +个除; 以外的字符.使用否定字符类消除了对其后跟(?:$ |;)组的惰性点匹配的需要.注意，该 * 量词使该值成为可选值.如果需要，请使用 + .

• ([_a-z]\w*) - Group 1 matching an identifier starting with _ or a letter and followed with 0+ alphanumeric/underscore symbols
• : - a colon
• \s* - 0+ whitespaces
• ([^;]*) - 0+ characters other than ;. The use of a negated character class eliminates the need of using lazy dot matching with (?:$|;) group after it. NOTE that * quantifier makes the value optional. If it is required, use +.

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