如何在Javascript中编写1到1000的奇数和偶数的脚本? [英] How to do a script for odd and even numbers from 1 to 1000 in Javascript?

查看:140
本文介绍了如何在Javascript中编写1到1000的奇数和偶数的脚本?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在学习一本带有已解决示例的Javascript,但是有一个没有解决方案的示例.我想知道怎么做...

I am studying a book of Javascript with solved examples but there is one example without solution. I would like to know how to do it ...

在JavaScript(在浏览器中)中,我应该做的是写1-1000的偶数,完成后写1-1000的奇数...我不确定如何在数字之间添加很小的暂停"书写以及如何知道第一个循环是否结束并开始写奇数?

In javascript (in browser) I should do is write even numbers from 1-1000 and after it is finished write odd numbers from 1-1000 ... I am not sure how to add there very small "pause" between number writing and how to know if first cycle is over and start writing odd numbers?

这是我的开始方式:

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
 <head>
   <title>Test</title>
 </head>
 <body>
<script type="text/javascript">
/* <![CDATA[ */
var i;
for (i = 0; i < 1000; i++)
if ((i % 2) == 0)
  document.writeln(i);

/* ]]> */
</script>
 </body>
</html>

推荐答案

尝试一下:

 function partA() {
        for (var i = 0; i < 1000; i++){
            if ((i % 2) == 0) document.write(i + ' ');
        }
        window.setTimeout(partB,1000)
    }

    function partB() {
        for (var i = 0; i < 1000; i++){
            if ((i % 2) !== 0) document.write(i + ' ');
        }
    }

    partA();


旁注:

仅将 document.write 用于测试.如果执行它,则在加载的HTML文档上,所有HTML元素都将被覆盖.(如您在我的示例中所见)

Use document.write for testing only. If you execute it, on a loaded HTML document, all HTML elements will be overwritten. ( As you can see in my example )

这篇关于如何在Javascript中编写1到1000的奇数和偶数的脚本?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆