如何正确退订socket.io房间并将其销毁? [英] How to correctly unsubscribe from a socket.io room and destroy it?

问题描述

每个套接字都有一个内部循环:

I have an internal loop for each socket:

if (!chat.room.list[hash]) { // room has expired
    socket.leave(hash);
    delete chat.user.list[socket.store.data.id].rooms[hash];
    delete socket.store.data.inRooms[hash]; // delete room hash from user store
}

socket.leave(hash)不执行任何操作-套接字仍接收发送到 hash 房间的消息.

socket.leave(hash) does nothing - socket still receives messages sent to hash room.

作为旁注-如果我与客户端Anna和客户端Bob相连-都接收消息，但是如果我与客户端Bob重新连接-Bob无法将消息发送给Anna.

As a side note - if I connect with client Anna and client Bob - both receive messages, but if I reconnect with client Bob - Bob cannot send messages to Anna.

在某处是否有完整的套接字io API文档(因为我找不到socket.leave(room)示例)?

Is there somewhere a full socket io API documentation (as I couldn't find socket.leave(room) examples)?

知道了！套接字IO使用斜杠保存房间句柄，因此您必须使用 socket.leave('/'+ hash)

Got it! Socket IO saves room handles with slash, so you have to use socket.leave('/'+hash)

推荐答案

socket.io中的房间是隐式创建和隐式删除的.基本上，当它们为空时，它们会被自动删除.

Rooms in socket.io are implicitly created and implicitly deleted. Basically they are automatically removed when they are empty.

是的，在内部将先前的/添加到房间名称中，但是您不需要需要添加此名称以从房间中移除插座.

And yes, a preceding / is added to the rooms name internally but you do not need to add this to remove a socket from a room.

每当创建一个房间时，尝试触发 console.log(io.sockets.manager.rooms)来查看内部发生的情况.

Try firing console.log(io.sockets.manager.rooms) whenever a room is created to have a look at what's happening internally.

这篇关于如何正确退订socket.io房间并将其销毁?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！