具有类似结构的XML的JAXB [英] JAXB for XMLs with similar structure

问题描述

我们正在使用JAXb来解析不具有模式的XML ...

We are using JAXb for parsing XMLs without schema...

我们处理的一种XML如下:

One of the XMLs we deal with looks like this:

<Trade>
    <Something1>
         <!-- stuff here -->
    </Something1>
</Trade>

另一个像这样:

<Trade>
    <Something2>
         <!-- stuff here -->
    </Something2>
</Trade>

我们使用相同的Jaxb上下文，并解组将它们解析为对象，例如 Something1 和 Something2 ( Something1 和 Something2实现了一个名为 Something 的接口；解组的结果被强制转换为 Something .这两个对象在上下文中都是已知的).但是，根据解组程序首先找到哪个类，这两个XML最终都将解组到 Something1 或 Something2 对象.

We use the same Jaxb context and unmarshaller to parse these into objects, say Something1 and Something2 (Both Something1 and Something2 implement an interface called Something; the result of the unmarshalling is cast to Something. Both objects are -of course- known to the context). However, depending on which class is found first by the unmarshaller, both of these XMLs end up being unmarshalled to Something1 or Something2 objects.

我还尝试添加一些XML-> XSD生成的模式，但这是一个死胡同，因为在< Trade> 和其他几个标记之间存在这种冲突.我遇到的错误是:

I also tried adding some XML->XSD generated schema, but that was a dead end, as theres's this clash at <Trade> and several other tags. The error I was getting was like:

A schema cannot contain two global components with the same name; this schema contains two occurrences of ',Trade'.

有没有办法用JAXB统一处理两个结构相似的XML?

Is there no way to handle two similarly structured XMLs uniformly with JAXB?

谢谢.

推荐答案

您可以这样编写Trade元素的类:

You can write the class for element Trade like this:

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "TradeType", propOrder = {
    "something1",
    "something2"
})
public class TradeType {
    @XmlElement(name = "Something1")
    protected Something1Type something1;
    @XmlElement(name = "Something2")
    protected Something2Type something2;
    // getters, setters
}

顺便说一句，这是编译(xjc)此XML模式时得到的:

BTW, this is what you get when you compile (xjc) this XML schema:

<xs:complexType name="TradeType">
  <xs:choice>
    <xs:element name="Something1" type="Something1Type"/>
    <xs:element name="Something2" type="Something2Type"/>
  </xs:choice>
</xs:complexType>

您只有一个顶级元素Trade，可以通过将 trade.getSomethingX()与null进行比较来区分(解组后).

You'll just have a single top-level element Trade, and the distinction (after unmarshalling) can be made by comparing trade.getSomethingX() with null.

如果Something1Type和Something2Type类型相同(不是相似")，则可以使用相同的 class (而不是接口).

If types Something1Type and Something2Type are identical (not "similar"), you could use the same class (not the interface).

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