如何使用jq通配符 [英] How to use jq wildcard

问题描述

我有以下json:

{  
   "details":{  
      "car": "bmw",
      "addresses":{  
         "ext-118-21-8-0-29":[  
            {  
               "version":4,
               "addr":"89 Psr"
            },
            {  
               "version":6,
               "addr":"56 apT"
            }
         ]
      }
   }
}

键 ext-118-21-8-0-29 是动态的，下次它将更改，我不知道确切的值，这就是为什么我需要使用通配符.我需要获取键 addr 的值，其中版本为 4 .

The key ext-118-21-8-0-29 is dynamic it will change the next time and I don't know the exact value, that's why I need to use wildcard. I need to get the value of the key addr where version is 4.

我期望输出为 89 Psr

我使用功能 startswith()尝试了以下操作.

I tried the following using the function startswith().

jq '.detail.addresses | select(startswith("ext"))'

但是它以错误结尾.

jq:错误(在:0处):startswith()需要字符串输入

jq: error (at :0): startswith() requires string inputs

推荐答案

如果您不关心要搜索的对象中的键，则可以使用 [] ，然后可以过滤到所需的结果.

If you don't care about the keys in the object you're searching, you could just search the values of the object using [] which you could then filter to your desired results.

.details.addresses[][] | select(.version == 4).addr

另一方面，如果您想选择具有版本4的键，则可以使用 to_entries 进行此操作:

If on the other hand you wanted to select keys that has a version 4, you could use to_entries to do this:

.details.addresses | to_entries[] | select(any(.value[]; .version == 4)).key

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