如何在我的代码中测试Junit try catch块 [英] How to Junit test a try catch block in my code

问题描述

我有一个带有几个方法的类，每个方法都有一个try catch块来查找任何异常.

I have a class with couple of methods and each with a try catch block to look for any exceptions.

代码如下:

public ResponseEntity get() {

    try {
        .....
    } catch (Exception e) {

        output = new ResponseEntity<>(HttpStatus.INTERNAL_SERVER_ERROR);
    }

    return output;
}

然后我想出了一个使用Mokito的测试用例来测试上述情况，但困惑了如何进入上述内容的捕获块

and I came up with a test case using Mokito to test the above scenario but confused how to enter into catch block of the above

@Test
public void testgetAllUsers_withoutexecp() {
    when(sMock.getAll()).thenReturn(someList);
    Assert.assertTrue(result.getStatusCode() ==  HttpStatus.OK );
}
@Test(expected=NullPointerException.class)
public void testgetAllUsers_execp() {
    when(sMock.getAll()).thenReturn(null);
    Assert.assertFalse(result.getStatusCode() ==  HttpStatus.OK );

}

我试图引发NullPointerException，但是仍然在代码覆盖范围中忽略了catch块(据此我假设未对其进行测试).请帮助我编写一个Junit测试用例，以使其进入异常.我对所有这些主题都很陌生.

I tried to raise a NullPointerException but still the catch block is left out in codecoverage (by which I assume it is not been tested). please help me to write a Junit test case for this to enter exception. I am very new to all these topics.

推荐答案

您可以使用 Mockito 的 thenThrow 子句引发异常:

You can raise exception using thenThrow clause of Mockito:

when(serviceMock.getAllUser()).thenThrow(new NullPointerException("Error occurred"));

然后断言如下:

Assert.assertTrue(result.getStatusCode() ==  HttpStatus.INTERNAL_SERVER_ERROR);

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