在Laravel 5中找不到用户类别 [英] User Class not found in Laravel 5
问题描述
我遇到以下问题.我刚刚从4.2升级到Laravel 5，但是我刚复制到新Controllers文件夹的UserController不起作用.
它总是告诉我它没有破坏用户模型.
我的代码在复制后看起来如下:
UserController.php
<?php使用App \ Transformer \ UserTransformer;UserController类扩展了ApiController{公共功能index(){App :: abort(403，'这是不允许的');}公共功能表演($ id){$ user =用户:: find($ id);if($ user-> access_token！= Input :: get('access_token')){返回不允许访问其他用户的数据"；}别的{$ result = $ this-> respondWithItem($ user，new UserTransformer);返回$ result;}}公共函数getID(){$ user = User :: where('email'，'='，Input :: get('email'))-> first();if($ user-> access_token！= Input :: get('access_token')){返回不允许访问其他用户的数据"；}别的{$ result = $ user-> id;返回$ result;}}公共功能寄存器(){$ user =新用户；$ name =输入:: get('name');$ email =输入::: get('email');$ password =输入::: get('password');if($ name！= null AND $ email！= null AND $ password！= null){if(User :: where('email'，'='，Input :: get('email'))-> exists()){返回使用此电子邮件的用户已存在"；}别的{$ user-> name = $ name;$ user-> email = $ email;$ user->密码= $密码;$ user-> save();返回成功"；}}别的{返回所有字段均为必填"；}}公共功能login(){$ user = User :: where('email'，'='，Input :: get('email'))-> first();if($ user！= null){if($ user-> password == Input :: get('password')){$ then = $ user->时间;$ now = strtotime("now");$ thenTimestamp = strtotime($ then);$ difference = $ now-$ thenTimestamp;if((空($ user-> date)AND空($ user-> time))OR($ difference> = 10800)OR($ user-> date！= date('dmY'))){$ user-> access_token = self :: getGUID();$ timestamp = time();$ user-> date = date("d.m.Y"，$ timestamp);$ timestamp = strtotime("now");$ user-> time = date('H:i'，$ timestamp);$ user-> save();}返回$ user-> access_token;}别的返回用户名或密码错误"；}别的返回用户名或密码错误"；}函数getGUID(){如果(function_exists('com_create_guid')){返回com_create_guid();}别的{mt_srand((double)microtime()* 100000);$ charid = strtoupper(md5(uniqid(rand()，true))));$连字符= chr(45);$ uuid =substr($ charid，0，8).$连字符.substr($ charid，8，4).$连字符.substr($ charid，12，4).$连字符.substr($ charid，16，4).$连字符.substr($ charid，20,12);返回$ uuid;}}公共功能check(){$ user = User :: where('access_token'，'='，Input :: get('access_token'))-> first();if($ user！= null){}别的返回无会话"；}} 我没有给Controller命名空间，而User Model就是开箱即用的.UserTransformer确实包含用户模型.这里是原始副本:
<?php使用应用程序\用户；使用League \ Fractal \ TransformerAbstract;类UserTransformer扩展TransformerAbstract{/***将此项目对象转换为通用数组** @返回数组*/公共功能转换(用户$ user){返回 ['id'=>(int)$ user-> id，'名称'=>$ user->名称，'email'=>$ user->电子邮件，'电话'=>$ user-> img，'mobile'=>$ user->移动，'地址'=>$ user->地址，];}} 这就是我需要的所有功能.
但是现在在Laravel 5中，UserController确实告诉我找不到User类.我试图将类似使用应用程序/用户"或使用应用程序/Http/Controllers/用户"的行添加到UserController中.这没用.我不确定为什么自从包含变压器后，我没有收到任何错误，但用户无法正常工作.我还尝试了不同的使用方法，将用户模型包含到Transfomer中，因为虽然可能会出现错误，但我没有可用的版本.
我希望有人能帮助我.
让我们澄清一些可能会干扰控制器加载的事情.
路由:默认情况下，laravel随附一个名为 RouteServiceProvider 的提供程序，该提供程序位于 app \ providers 中.如果查看此文件，将会发现有一个名为 $ namespace 的变量.如果您想在 routes.php 文件中获得更多清晰"的路由，这将非常有用.例如，将 $ namespace ='App \ Http \ Controllers'转换为...
Route :: get('welcome'，'App \ Http \ Controllers \ HomeController @ welcome'); 对此...
Route :: get('welcome'，'HomeController @ welcome'); 是的，写规则的一个简短选择.默认情况下， $ namespace 的值设置为 {Application Name} \ Http \ Controllers
控制器:如果您的laravel安装正在与 RouteServiceProvider 配合使用，则将永远找不到您的控制器，因为路由会在先前声明的命名空间之前添加前缀.那么，我应该在控制器中使用哪个名称空间?有两种选择:
-
遵循laravel 5的约定，将您的控制器放在
app/Http/Controllers/文件夹中.然后，将名称空间声明为默认名称:命名空间{Application Name} \ Http \ Controllers;并将其设置在
routes.php上，例如://天气是控制器路线:: get('foo'，'UserController @ index');//天气是一种资源路线:: resource('api-user'，'UserController');请注意，名称空间结构与它所在的文件夹结构(Http/Controllers/)相匹配
-
从providers文件夹中删除
RouteServiceProvider并将其从config/app.php文件中的providers数组中删除.然后，您可以使用绝对"名称空间，例如:命名空间{Application Name} \ Http \ Controllers;路线:: get('foo'，'Myapp \ Http \ Controllers \ UserController @ index');
应用程序名称和自动加载
您是否对自己提出疑问，为什么未在名称空间中添加 app 文件夹?看看composer.json文件:
自动加载":{类图":[数据库"]，"psr-4":{"MyCoolApp \\":"app/"}}， 如果您注意到的话，您会看到有一个别名指向 app/文件夹.因此，for app将响应别名而不是 app \ Http \ Controllers .我不是这个主题的专家，希望有人帮我扩展这个解释，但是我已经读过 psr-4 就像一条规则，使您将命名空间与文件夹结构进行匹配.结果，如果您的控制器就像...
命名空间MyCoolApp \ Http \ Classes; 自动加载类期望您的控制器驻留在 app/Http/Classes/而不是 MyCoolApp/Http/Controllers
这就是找不到控制器的原因.
I have got the following Problem. I have just upgraded to Laravel 5 from 4.2 but my UserController which I first just copied to the new Controllers folder does not work.
It always tells me that it does not fiend the User Model.
My Code looked like the following when I copied it:
UserController.php
<?php
use App\Transformer\UserTransformer;
class UserController extends ApiController
{
public function index()
{
App::abort(403, 'This is not allowed');
}
public function show($id)
{
$user = User::find($id);
if($user->access_token!=Input::get('access_token')){
return "It is not allowed to access data from other users";
}else{
$result = $this->respondWithItem($user, new UserTransformer);
return $result;
}
}
public function getID()
{
$user = User::where('email', '=', Input::get('email'))->first();
if($user->access_token!=Input::get('access_token')){
return "It is not allowed to access data from other users";
}else{
$result = $user->id;
return $result;
}
}
public function register()
{
$user = new User;
$name = Input::get('name');
$email = Input::get('email');
$password = Input::get('password');
if($name != null AND $email != null AND $password != null){
if(User::where('email', '=', Input::get('email'))->exists()){
return "A user with this email already exists";
}else{
$user->name = $name;
$user->email = $email;
$user->password = $password;
$user->save();
return "Success";
}
}else{
return "All fields are required";
}
}
public function login(){
$user = User::where('email', '=', Input::get('email'))->first();
if($user != null){
if($user->password==Input::get('password')){
$then =$user->time;
$now = strtotime("now");
$thenTimestamp = strtotime($then);
$difference = $now - $thenTimestamp;
if((empty($user->date) AND empty($user->time))OR($difference >=10800)OR($user->date!=date('d.m.Y'))){
$user->access_token=self::getGUID();
$timestamp = time();
$user->date=date("d.m.Y",$timestamp);
$timestamp = strtotime("now");
$user->time=date('H:i', $timestamp);
$user->save();
}
return $user->access_token;
}
else
return "Wrong username or password";
}else
return "Wrong username or password";
}
function getGUID(){
if (function_exists('com_create_guid')){
return com_create_guid();
}else{
mt_srand((double)microtime()*100000);
$charid = strtoupper(md5(uniqid(rand(), true)));
$hyphen = chr(45);
$uuid =
substr($charid, 0, 8).$hyphen
.substr($charid, 8, 4).$hyphen
.substr($charid,12, 4).$hyphen
.substr($charid,16, 4).$hyphen
.substr($charid,20,12);
return $uuid;
}
}
public function check(){
$user = User::where('access_token', '=', Input::get('access_token'))->first();
if($user != null){
}else
return "no session";
}
}
I did not have the the Controller namespaced and the User Model just worked out of the box. The UserTransformer does have the User Model included. Here the original copy:
<?php
use App\User;
use League\Fractal\TransformerAbstract;
class UserTransformer extends TransformerAbstract
{
/**
* Turn this item object into a generic array
*
* @return array
*/
public function transform(User $user)
{
return [
'id' => (int) $user->id,
'name' => $user->name,
'email' => $user->email,
'phone' => $user->img,
'mobile' => $user->mobile,
'address' => $user->address,
];
}
}
That is everything that I needed to have the functions to work.
But now in Laravel 5 the UserController does tell me that the User class is not found. I have tried to add lines like this "use App/User" or "use App/Http/Controllers/User" to the UserController. It did not work. I am not sure why since I have got my Transformer included I do not get any error for this but the User does not work. I have also tried different use methods to include the User Model into the Transfomer since I though there might be an error but I do not get a working version.
I hope someone can help me.
Let's clarify just some things that could be interfering in loading the controller.
The route: by default, laravel comes with a provider called RouteServiceProvider found at app\providers. If you take a look to this file you will find that there is a variable named $namespace. This is very usefull if you want get more "clear" routes at routes.php file. For example, having $namespace = 'App\Http\Controllers' you convert this...
Route::get('welcome', 'App\Http\Controllers\HomeController@welcome');
to this...
Route::get('welcome', 'HomeController@welcome');
So yes, a short choice for write your rules. By default, the value of $namespace is set to {Application Name}\Http\Controllers
The controller: If you laravel installation is working with the RouteServiceProvider then your controller never will be found, because the routes prefix the namespace previously declared. So, which namespace should I use in controllers? there are two options:
Following the conventions of laravel 5 putting your controller at
app/Http/Controllers/folder. Then, declare the namespace as default:namespace {Application Name}\Http\Controllers;and setting it at
routes.phplike:// weather is a controller Route::get('foo', 'UserController@index'); // weather is a resource Route::resource('api-user', 'UserController');Notice that the namespace structure match the same folder structe where it is resides (Http/Controllers/)
Delete
RouteServiceProviderfrom providers folder AND delete it from providers array inconfig/app.phpfile. Then, you can use "absolute" namespaces like:namespace {Application Name}\Http\Controllers; Route::get('foo', 'Myapp\Http\Controllers\UserController@index');
Application name and autoload
did you question yourself why app folder is not added at namespace? Take a look the composer.json file:
"autoload": {
"classmap": [
"database"
],
"psr-4": {
"MyCoolApp\\": "app/"
}
},
If you note, you will see that there is an alias that points out to app/ folder. So, for app will response to the alias instead of app\Http\Controllers.
I am no expert in this topic, hope somebody give me hand to expand this explanation, but I have read that psr-4 is like a rule that make you match the namespace with the folder structure. As result, if your controller is like...
namespace MyCoolApp\Http\Classes;
The autoload class expects that your controller resides at aapp/Http/Classes/ instead of MyCoolApp/Http/Controllers
That is a reason why a controller could not be found.
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