访问自定义规则类中的另一个请求的输入-Laravel [英] Access to another requested input in custom rule class - Laravel

问题描述

我需要通过pass方法访问 $ request->重要.我需要它来基于此值验证名称

I need to access $request->important in passes method. I need it to validate name based on this value

class TestCustom implements Rule
{
    public function passes($attribute, $value)
    {
        // 
    }

    public function message()
    {
        return 'some txt';
    }
}

像这样使用:

use App\Rules\TestCustom;

$request->validate([
    'name' => ['required', new TestCustom],
    'important' => ['required', 'string'],
]);

推荐答案

最好将数据传递给规则构造函数，然后在规则内部使用它.这样，您就可以使用规则来验证不同的数据源，以防万一它不是来自请求.

It's much better to pass data to rule constructor and use it inside rule afterwards. This way you can use rule to validate different data sources, in case if it comes not from request.

class TestCustom implements Rule
{
    private $data;

    public function __construct(array $data)
    {
        $this->data = $data;
    }

    public function passes($attribute, $value)
    {
        // Use $this->data['important'] for validation
    }

    public function message()
    {
        return 'some txt';
    }
}

然后将数据传递给规则:

Then pass data to rule:

使用App \ Rules \ TestCustom;

use App\Rules\TestCustom;

$request->validate([
    'name' => ['required', new TestCustom($request->all())],
    'important' => ['required', 'string'],
]);

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