React Router Lazy Component无法正常工作 [英] React Router Lazy Component isn't working

问题描述

这可行:

import Page from 'components/Page';
...

render() {
   return (
     <Route render={props => <Page {...props}/>}/>
   );
}

但这不是:

import React, { lazy } from 'react';
const Cmp = lazy(() => import('components/Page'));
...

render() {
   return (
     <Route render={props => <Cmp {...props}/>}/>
   );
}

反应16.8.6React Router 5.0.0

React 16.8.6 React Router 5.0.0

我明白了:

The above error occurred in one of your React components:
    in Unknown (at configured.route.js:41)
    in Route (at configured.route.js:41)
    in ConfiguredRoute (created by Context.Consumer)
    ...rest of stack trace

有人可以看到我在这里做什么愚蠢的事情吗?

Can anyone see what stupid thing I am doing here?

推荐答案

引用 与代码拆分相关的文档 ，建议您将 Suspense 与已定义的 fallback 结合使用，这样您就可以在尚未加载的组件上进行渲染.

Referencing the React Docs on code splitting, the recommendation is to use Suspense with a defined fallback so you have something to render in place of the components when they haven't loaded.

// Direct paste from https://reactjs.org/docs/code-splitting.html

import { BrowserRouter as Router, Route, Switch } from 'react-router-dom';
import React, { Suspense, lazy } from 'react';

const Home = lazy(() => import('./routes/Home'));
const About = lazy(() => import('./routes/About'));

const App = () => (
  <Router>
    <Suspense fallback={<div>Loading...</div>}>
      <Switch>
        <Route exact path="/" component={Home}/>
        <Route path="/about" component={About}/>
      </Switch>
    </Suspense>
  </Router>
);

暂记应该是使用 lazy

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