linux/list.h-如何安全地从列表中删除项目? [英] linux/list.h - How to safely remove items from the list?

问题描述

在 linux/list的注释中.h 写道:

1. 在使用 list_del_entry 时:注意:条目上的 list_empty 在此之后不返回true，条目处于未定义状态.
2. 对于 list_del :这仅用于内部列表操作，在此我们已经知道上一个/下一个条目！

1. On using list_del_entry: Note: list_empty on entry does not return true after this, the entry is in an undefined state.
2. For list_del: This is only for internal list manipulation where we know the prev/next entries already!

那么，我该如何安全地从链接列表中删除一个对象并确保 list_empty 正常工作，或确保下一个链接列表节点删除是正确的?

So, how would I safely remove an object from linked list and make sure that list_empty is functional or make sure that next linked list node deletion is correct?

这是我目前的实现方式

struct kool_list{
    int to;
    struct list_head list;
    int from;
};

struct kool_list *tmp;
struct list_head *pos, *q;
struct kool_list mylist;

list_for_each_safe(pos, q, &mylist.list){
         tmp= list_entry(pos, struct kool_list, list);
         printf("freeing item to= %d from= %d\n", tmp->to, tmp->from);
         list_del(pos);
         free(tmp);
}

推荐答案

我认为您误解了这些评论.第一个说 list_empty(& entry-> list)不会返回true.但是，如果从列表中删除所有元素(正确的方法)并执行 list_empty(& mylist.list)，结果将为真.

I think you misunderstand the comments. The first one says that list_empty(&entry->list) will not return true. However, if you remove all elements from the list (the way you do it is correct) and do list_empty(&mylist.list) you will get true as a result.

如果出于某种原因您希望将条目的 struct list_head 保持在内部一致的状态，请使用 list_del_init .

If for some reason you want to keep the entry's struct list_head in an internally consistent state, use list_del_init.

第二， __ list_del 仅供内部使用， list_del 是公平的游戏.

Secondly, __list_del is for internal usage only, list_del is fair game.

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