如何在特定位置根据相似项目排列列表 [英] How can I arrange the list according to similar item in certain location

问题描述

我想安排第二部分="1_1man:Army"的测试"列表项，它们具有相似的词，然后对其进行排列，以使"1_1man:Army"之后的值即堆栈"的值测试"在新列中彼此相邻.

I wanted to arrange the "test" list items for the second part = "1_1man:Army" which have similar words and then arrange it so that the values after "1_1man:Army" which is the values for "stack" and "testing" to be next to each other in a new column.

输入:

test = [[[0.52, '1_1man::army'], 'stack'], 
    [[0.45, '3_3man::army'], 'flow'], 
    [[0.52, '1_1man::army'], 'testing'], 
    [[0.52, '2_2man:army'], 'expert']]

代码:

for x in test:
print(x[0][1])

预期输出:

打印(测试)

test = [[[0.52, '1_1man::army'], 'stack', 'testing'], 
        [[0.45, '3_3man::army'], 'flow'], 
        [[0.52, '2_2man:army'], 'expert']]

任何人都可以帮助我.如果可能，请按照整数值(0.45,0.52)升序排列

Could anyone assist me please. If possible to arrange it in ascending order according to the integer value (0.45,0.52)

排序输出:

test = [[[0.45, '3_3man::army'], 'flow'],
[[0.52, '1_1man::army'], 'stack', 'testing'], 
[[0.52, '2_2man:army'], 'expert']]

已更新:

如果要使用下面Rahul所示的示例，如何加载它?

How can I load it if I want to use the example shown by Rahul at below?

我的文本文件就是这样

[0.52, '1_1man::army'], 'stack'] 
[0.45, '3_3man::army'], 'flow']
[0.52, '1_1man::army'], 'testing'] 
[0.52, '2_2man:army'], 'expert']

如何加载它?

推荐答案

您可以使用 groupby ，

In [41]: from itertools import groupby
In [42]: for g,val in groupby(sorted(test,key=lambda x:x[0][1]),key=lambda x:x[0][1]):
    ...:     g_values = list(val)
    ...:     keys = [i[1] for i in g_values]
    ...:     print list([g_values[0][0]] + keys)
    ...:     
    ...:     
[[0.52, '1_1man::army'], 'stack', 'testing']
[[0.52, '2_2man:army'], 'expert']
[[0.45, '3_3man::army'], 'flow']

sorted 在这里很重要，对于 groupby ，它将仅与调整元素分组.而lambda函数用于识别分组密钥.

sorted is important here, For groupby it will group with adjusting elements only. And lambda function used to identify the grouping key.

编辑1

根据您的问题进行的修改.如果您需要根据浮点值进行排序.

As per the modification made in your question. If you need to sort based on the float value.

In [60]: result = []
In [58]: for g,val in groupby(sorted(test,key=lambda x:x[0][1]),key=lambda x:x[0][1]):
    ...:     g_values = list(val)
    ...:     keys = [i[1] for i in g_values]
    ...:     result.append(list([g_values[0][0]] + keys))
    ...:     

In [60]: sorted(result,key=lambda x:x[0][0])
Out[60]: 
[[[0.45, '3_3man::army'], 'flow'],
 [[0.52, '1_1man::army'], 'stack', 'testing'],
 [[0.52, '2_2man:army'], 'expert']]

编辑2

如果您正在读取文件.

In [83]: from ast import literal_eval

In [84]: fp = open('file_name.txt')

In [85]: test = [literal_eval(i) for i in fp.readlines()]

最终解决方案将是这样.

Final Solution will be like this.

from ast import literal_eval
fp = open('file_name.txt')
test = [literal_eval(i) for i in fp.readlines()]
result = []
for g,val in groupby(sorted(test,key=lambda x:x[0][1]),key=lambda x:x[0][1]):
    g_values = list(val)
    keys = [i[1] for i in g_values]
    result.append(list([g_values[0][0]] + keys))
print(sorted(result,key=lambda x:x[0][0]))

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