如何遍历第二个数字 [英] How to iterate over every second number

问题描述

在阅读文档时，我注意到一句话:"Rust没有 C风格用于循环.".因此，我想知道如何使循环等效于 for(i = 0; i< 10; i + = 2){} ?

Reading the docs, I noticed a sentence saying: "Rust doesn't have a C style for loop.". So, I wonder, how can I make a loop equivalent to for(i = 0; i < 10; i += 2) { }?

我能想到的方法是:

for i in 0..10 {
    if i % 2 == 0 {
        //Do stuff
    }
}

甚至:

let i = 0;
loop {
    if i < 10 {
        //Do stuff
        i += 2;
    } else {
        break;
    }
}

但是我不确定这是最好的方法，尤其是因为它确实很冗长.有更好的方式吗?我猜想是迭代器，但是我不确定该怎么做.

But I'm not sure this is the best way, especially since it's really verbose. Is there a better way? I'm guessing it would be with iterators, but I'm not sure how I'd do that.

推荐答案

有

There's std::iter::range_step right now, but it's marked as unstable with the message "likely to be replaced by range notation and adapters".

fn main() {
    for i in std::iter::range_step(0, 10, 2) {
        println!("{:?}", i);
    }
}

打印

0
2
4
6
8

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