./lua/addtest.lua:9:尝试索引本地"testobj"(一个userdata值)]] [英] ./lua/addtest.lua:9: attempt to index local 'testobj' (a userdata value)]]

问题描述

test.exe调用addTest.lua并将 lua_testobj 设置到表中，然后addTest.lua调用testobj.dll，但是testobj.dll无法获取"lua_testobj"

test.exe call addTest.lua and set the lua_testobj to the table, and addTest.lua call testobj.dll, but testobj.dll can not get the "lua_testobj"

错误消息是

addTest.lua:9尝试索引本地'testobj'(一个用户数据值)

addTest.lua:9 attempt to index local 'testobj' (a userdata value)

1. test.exe

1. test.exe

L = luaL_newstate();
// link lua lib
luaL_openlibs(L);
//
addLuaCPath( L, "./clib/?.dll" );
//
lua_pushlightuserdata(L, (void*)g_TestObj.get()); // g_TestObj is a global vars
lua_setfield(L, LUA_REGISTRYINDEX, "lua_testobj");
// 
int err = 0;
err = luaL_loadfile( L, "./lua/addTest.lua" );
if( err != LUA_OK )
  printf("Failed to load addTest.lua![%s]", lua_tostring(L,-1));

err =  lua_pcall( L, 0, 1, 0 );
if( err != LUA_OK )
  printf("Failed to call addTest.lua![%s]", lua_tostring(L,-1));

addtest.lua代码如下

the addtest.lua code is following

local luapath = package.path
local cpath = package.cpath

print(luapath)
print(cpath)

local testobj= require "testobj"

testobj.addTest()

，下面是testobj.dll源代码

and the testobj.dll source code is following

static int laddTest(lua_State *L)
{
  lua_getfield(L, LUA_REGISTRYINDEX, "lua_testobj");
  return 1;
}

extern "C" int __declspec(dllexport) 
luaopen_testobj(lua_State *L)
{
  luaL_Reg l[] = {
    { "addTest", laddTest },
    { NULL, NULL },
  };

  luaL_checkversion(L);
  luaL_newlib(L,l);

  lua_getfield(L, LUA_REGISTRYINDEX, "lua_testobj");
  CTestObj* pTestObj = static_cast<CTestObj*>( lua_touserdata(L,-1) );

  return 1;
}

推荐答案

看来 testobj.dll 实际上确实成功返回了 lua_testobj ，因为您得到的错误:

It looks like testobj.dll did actually return your lua_testobj successfully because the error you're getting:

addTest.lua:9尝试索引本地'testobj'(一个用户数据值)

addTest.lua:9 attempt to index local 'testobj' (a userdata value)

表示lua将 testobj 视为 userdata .那不是问题所在.真正的问题是您没有将任何元表与该用户数据相关联，因此当脚本尝试使用lua时，lua不能对其进行任何操作.

indicates lua sees testobj as a userdata. That's not where the problem is; the real issue is that you didn't associate any metatable with that userdata so lua can't really do anything with it when a script tries to use it.

我已经修改了您的 luaopen_testobj 来为您的 testobj 创建并注册一个元表:

I've modified your luaopen_testobj to create and register a metatable for your testobj:

extern "C" int __declspec(dllexport) 
luaopen_testobj(lua_State *L) 
{
  luaL_Reg l[] = 
  {
      { "addTest", laddTest },
      { NULL, NULL },
  };

  luaL_checkversion(L);
  lua_pushlightuserdata(L, (void*)g_TestObj.get());

  // g_TestObj, testobj_mt, {l}
  luaL_newmetatable(L, "lua_testobj");
  luaL_newlib(L, l);
  // testobj_mt.__index = {l}
  lua_setfield(L, -2, "__index");

  // return setmetatable(g_TestObj, testobj_mt)
  lua_setmetatable(L, -2);
  return 1;
}

这应该允许您使用lua中的 testobj:addTest()访问 laddTest . laddtest 应该检查 testobj 确实是您传入的用户数据，例如:

This should allow you to access laddTest using testobj:addTest() from lua. laddtest should check that testobj is indeed the userdata you passed in, for example:

static int laddTest(lua_State *L)
{
    auto pTestObj = reinterpret_cast<CTestObj *> (luaL_checkudata(L, 1, "lua_testobj"));
    // do something ...
    return 1;
}

这篇关于./lua/addtest.lua:9:尝试索引本地"testobj"(一个userdata值)]]的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！