如何在Python 3中将SubElement的内容包装在XML标记中? [英] How do I wrap the contents of a SubElement in an XML tag in Python 3?
问题描述
我有一个示例XML文件,如下所示:
I have a sample xml file like this:
<root>
She
<opt>went</opt>
<opt>didn't go</opt>
to school.
</root>
我想创建一个名为的子元素,并将其中的所有内容放入其中.也就是说,
I want to create a subelement named of , and put all the contents of into it. That is,
<root>
<sentence>
She
<opt>went</opt>
<opt>didn't go</opt>
to school.
</sentence>
</root>
我知道用ElementTree或lxml制作子元素很热,但是我不知道如何从她"到学校"中进行选择.全部一次.
I know hot to make a subelement with ElementTree or lxml, but I have no idea of how to select from "She" to "shools." all at once.
import lxml.etree as ET
ET.SubElement(root, 'sentence')
I'm lost...
推荐答案
您可以反过来解决:(而不是添加子元素,而是添加新的父元素.)我的意思是,更改 root
标记为 sentence
,创建一个新的 root
元素,并插入旧的 root
(现在为 sentence
)进入新的root
:
You could go about it in reverse: (Instead of adding a subelement, add a new parent.) By that I mean, change the root
tag to sentence
, create a new root
element, and insert the old root
(now sentence
) into the new root
:
import lxml.etree as ET
content = '''\
<root>
She
<opt>went</opt>
<opt>didn't go</opt>
to school.
</root>'''
root = ET.fromstring(content)
root.tag = 'sentence'
newroot = ET.Element('root')
newroot.insert(0,root)
print(ET.tostring(newroot))
# <root><sentence>
# She
# <opt>went</opt>
# <opt>didn't go</opt>
# to school.
# </sentence></root>
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